javascript jquery url part trimming

Question

I have a url like

http://www.blah.com/something/maybesomethingelse/Webservices/something.asmx/blah

That is being passed through a jquery ajax request.

I want to remove everything after /Webservices/ so I can stick a new page in for error handling.

so ideally this would return

http://www.blah.com/something/maybesomethingelse/Webservices/

Then i could just concat on the new page.

Thanks for your help :)

Simple way: url = url.split(/\/Webservices\/)[0]+"/Webservices/"+yourstuff — mplungjan
– mplungjan, Commented Mar 23, 2011 at 14:16
@mplungjan: that comment seems worthy of being an answer +1 for the comment, and an up-vote on your answer (should you post it) =] — David Thomas
– David Thomas, Commented Mar 23, 2011 at 14:30
@David: Thanks :) I was sure that if I posted it, some jQuery or RegEx purists would downvote it as far as they could ;) — mplungjan
– mplungjan, Commented Mar 23, 2011 at 14:36

mplungjan · Accepted Answer · 2011-03-23 14:35:30Z

2

Simple way: url = url.split(/\/Webservices\/)[0]+"/Webservices/"+yourstuff

or neater

var lastFolder = "/Webservices/";
url = url.split(lastFolder)[0]+lastFolder+yourstuff;

answered Mar 23, 2011 at 14:35

mplungjan

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Comments

abieganski · Accepted Answer · 2011-03-23 14:27:11Z

1

You could use a parser like this one:

but in this simple case, you only need to find the last index of "/Webservices/":

var lastIndex = url.lastIndexOf('/Webservices/')

and then take everything from the beginning up to the end of "/Webservices/":

var baseUrl = url.substring(0, lastIndex + 12)

and then append the new page:

var newUrl = baseUrl + '/Error.aspx'

answered Mar 23, 2011 at 14:27

abieganski

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