I am new to Python. I would to print all elements in list using a single line of code. You may use lambda function.
a = [1,2,3,4]
for each in a:
print(each)
Here, I used two lines of code What I want is a single line of code to get the same output (preferably lambda function)
output required:
1
2
3
4
Try this just using print:
print(*a, sep=' ')
print accepts sep key that will put between printing of each element of an iterable.
so the above code output will be
1 2 3 4
You can use ',' or \n(new line) to print between each charater.
it means:
print(*a, sep='\n')
output will be:
1
2
3
4
If you have to use lambda AT ANY PRICE, then (using Python 3):
a = [1,2,3,4]
list(map(lambda x:print(x),a))
However, if one liner is enough for you keep in mind that such code:
a = [1,2,3,4]
for each in a: print(each)
is legal Python code, producing same result.
Yet another option is converting int to str and joining them:
print('\n'.join(map(str,a)))
Try this print(''.join(map(str, a)))
print(*a, sep='\n')