PowerShell Output to CSV Not Placing Columns in Correct Order

Question

How do I code this to output the columns in this order:

unique_sis_group_id, unique_sis_user_id, unique_sis_school_id, mm_admin

My code:

$objs = @();
$output = Import-Csv -Path "c:\users\patrick\desktop\RelayFiles\RelayMemberships\file2concatenate.csv" | ForEach {
    $Object = New-Object PSObject -Property @{
        unique_sis_group_id  = [String]::Concat($_.unique_sis_group_id, $_.unique_sis_user_id)
        unique_sis_user_id = $_.unique_sis_school_id
        unique_sis_school_id = $_.mm_admin
        mm_admin = 0
    }
    $objs += $Object;
}
$objs
$objs | Export-Csv -NoTypeInformation c:\users\patrick\desktop\RelayFiles\RelayMemberships\memberships.csv

if you use either an [ordered] hashtable OR [better] the [PSCustomObject] type accelerator, you will get your props in the declared order. — Lee_Dailey
– Lee_Dailey, Commented Jan 26, 2019 at 0:01
@Lee_Dailey Note that both [ordered] and [PSCustomObject] are not available prior to PowerShell v3. — Ansgar Wiechers
– Ansgar Wiechers, Commented Jan 26, 2019 at 12:33

Ansgar Wiechers · Accepted Answer · 2019-01-26 12:34:11Z

1

You assign the ForEach-Object to $output, but nothing inside actually outputs something. Using a [PSCustomObject] is much simpler:

## Q:\Test\2019\01\25\SO_54373962.ps1
$CsvIn  = "c:\users\patrick\desktop\RelayFiles\RelayMemberships\file2concatenate.csv"
$CsvOut = "c:\users\patrick\desktop\RelayFiles\RelayMemberships\memberships.csv"
$output = Import-Csv -Path $CsvIn | ForEach-Object {
    [PSCustomObject]@{
         unique_sis_group_id  = [String]::Concat($_.unique_sis_group_id, $_.unique_sis_user_id)
         unique_sis_user_id   = $_.unique_sis_school_id
         unique_sis_school_id = $_.mm_admin
         mm_admin             = 0
    }
}
$output
$output | Export-Csv $CsvOut -NoTypeInformation

edited Jan 26, 2019 at 12:34

Ansgar Wiechers

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answered Jan 26, 2019 at 0:18

user6811411

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1 Comment

Patrick Harrison Over a year ago

Thank you for the lesson. Much appreciated!

Ansgar Wiechers · Accepted Answer · 2019-01-26 12:28:24Z

0

This took care of it. Is there a better way?

$objs =@();
$output = Import-Csv -Path "c:\users\patrick\desktop\RelayFiles\RelayMemberships\file2concatenate.csv" | ForEach {
    $Object = New-Object PSObject -Property @{
        unique_sis_group_id  = [String]::Concat($_.unique_sis_group_id, $_.unique_sis_user_id)
        unique_sis_user_id = $_.unique_sis_school_id
        unique_sis_school_id = $_.mm_admin
        mm_admin = 0
    }
    $objs += $Object;
}
$objs |
    Select-Object "unique_sis_group_id", "unique_sis_user_id",
        "unique_sis_school_id", "mm_admin" |
    Export-CSv -NoTypeInformation c:\users\patrick\desktop\RelayFiles\RelayMemberships\memberships.csv

edited Jan 26, 2019 at 12:28

Ansgar Wiechers

202k27 gold badges286 silver badges363 bronze badges

answered Jan 25, 2019 at 23:11

Patrick Harrison

33 bronze badges

1 Comment

Ansgar Wiechers Over a year ago

For PowerShell v2 and earlier Select-Object is the way to go, because the [ordered] and [PSCustomObject] type accelerators have been introduced with PowerShell v3 and aren't available in earlier versions. If you have PowerShell v3 or newer use the [PSCustomObject] type accelerator as described in this answer, which also avoids the pitfall of appending to an array in a loop.

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