I am working with an array of 8 bits and I am trying to convert it to a single char in Java. I am trying to do something along the lines of
byte[] bytes2 = {0,0,0,0,0,0,0,0};
char c = (char) bytes2);
It is throwing a compilation error that I can not case a byte[] to a char. I have gotten it to compile, but not work correctly by assigning char c to just one of the elements of the array. I am just stuck on this part, and would appreciate a little bit of help.
Thank you
byte[] is array of bytes, and 1 byte is 8 bit, 1 char is also 8 bit.
You initiate byte[] with {0,0,0,0,0,0,0,0}; It means your store 8 * 8 = 64 bits in bytes2 variable.
So you can't store 64 bits data into single char (8 bit).
But you can do this:
byte[] bytes2 = {0,0,0,0,0,0,0,0};
char c = (char) bytes2[0]; // store first element (8 bit) into single char (1 bit) and cast it.
You can't convert it to a one single char. Instead of that you can convert it to a single String and then convert that to a char array like below,
byte[] bits2 = {0, 0, 0, 0, 0, 0, 0, 0};
String value = new String(bits2);
char[] chars = value.toCharArray();
