Jest - Sequential Execution of a describe block

Question

I'm executing a describe() block using jest. between each test() I'd like to execute code in a synchronous manner, for example:

describe('matching cities to foods', () => {
  // Applies only to tests in this describe block
  beforeEach(() => {
    return initializeFoodDatabase();
  });
  
  const city = getCity();
  
  test('Vienna <3 sausage', () => {
    expect(isValidCityFoodPair(city, 'Wiener Schnitzel')).toBe(true);
  });
  
  let city2 = getCity2();

  test('San Juan <3 plantains', () => {
    expect(isValidCityFoodPair(city2, 'Mofongo')).toBe(true);
  });
});

function getCity(){
  return 'Vienna';
}

function getCity2(){
  return 'San Juan';
}

What I want is the code to be executed in the following sequence:

beforeEach
getCity
test
getCity2
test

Currently, the function calls between tests are being executed asynchronously. How is it possible to execute it in a sequential manner?

Duplicated of Question

Sivasankar
– Sivasankar

2019-01-28 10:29:15 +00:00
Commented Jan 28, 2019 at 10:29 — Sivasankar
– Sivasankar, Commented Jan 28, 2019 at 10:29

Cuong Vu · Accepted Answer · 2019-01-28 10:57:21Z

1

Maybe you misunderstood beforeEach. The beforeEach block will be called multiple times before each test(). So in your case, to execute tests in the following sequence:

beforeEach
getCity
test1
getCity2
test2

You can use beforeAll instead then call getCity() and getCity2() in appropriate test block like this:

describe('matching cities to foods', () => {
  // Applies only to tests in this describe block
  beforeAll(() => {
    return initializeFoodDatabase();
  });

  test('Vienna <3 sausage', () => {
    const city = getCity();
    expect(isValidCityFoodPair(city, 'Wiener Schnitzel')).toBe(true);
  });


  test('San Juan <3 plantains', () => {
    const city2 = getCity2();
    expect(isValidCityFoodPair(city2, 'Mofongo')).toBe(true);
  });
});

Check the docs for more info: https://jestjs.io/docs/en/setup-teardown

answered Jan 28, 2019 at 10:57

Cuong Vu

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