Array as function parameter error finding the length of the array [duplicate]

Question

1.  int minimum(int arr[]){
2.
3.     int min,pos = 0;
4.     min =  arr[0];
5.     int i;
6.     for(i = 0;i<(sizeof(arr)/sizeof(*arr));i++){
7.         if(arr[i]<min){
8.             min = arr[i];
9.             pos = i;
10.        }
11.     }
12.     return arr[pos];
13.  }

in the 6th line it the satement in the for loop condition cant count the size of the array .......

Are you using C or C++? If it's C++, then std::array<> is what you're looking for. Regular arrays are dumb as they do not know they're size (easily). — PaulMcKenzie
– PaulMcKenzie, Commented Feb 2, 2019 at 11:22
Here's some indormation how you can format your code properly when posting at this site. — πάντα ῥεῖ
– πάντα ῥεῖ, Commented Feb 2, 2019 at 11:24

bruno · Accepted Answer · 2019-02-02 11:39:14Z

0

int minimum(int arr[])

the number of elements is unknown at compile time, sizeof(arr) cannot values the right value, it will values sizeof(int *) because this is the type of arr

But in

void f()
{
   int arr[3];

   printf("%d\n", sizeof(arr)/sizeof(*arr));
}

the sizeof of arr is known at compile time

edited Feb 2, 2019 at 11:39

answered Feb 2, 2019 at 11:28

bruno

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2 Comments

Weather Vane Over a year ago

In int minimum(int arr[42]) the number of elements is still unknown by the compiler.

bruno Over a year ago

@WeatherVane yes, I wasn't enough clear, I edit, thank you for the advice

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