Dynamic path symfony

Question

I have this code:

href="{{ path('new') }}"

Now is necessary use one variable in this section:

href="{{ path(item.ruta) }}"

But this show a error:

An exception has been thrown during the rendering of a template ("Unable to generate a URL for the named route "" as such route does not exist.").

How can solution this problem?

It seems that item.ruta is empty, so no route could be generated. You could specifiy a fallback like this {{ path(item.ruta ? item.ruta : 'new') }} — Fabian Schmick
– Fabian Schmick, Commented Feb 4, 2019 at 15:07
Thanks Fabian. Now show this error with this code: "An exception has been thrown during the rendering of a template ("Unable to generate a URL for the named route "#" as such route does not exist.")." — juanitourquiza
– juanitourquiza, Commented Feb 4, 2019 at 15:10
It is not a solution, the item.ruta is inside a loop. The idea is to assign the content of item.ruta within path — juanitourquiza
– juanitourquiza, Commented Feb 4, 2019 at 15:20
What do you mean with The idea is to assign the content of item.route within path ? — Fabian Schmick
– Fabian Schmick, Commented Feb 4, 2019 at 15:21

Fabian Schmick · Accepted Answer · 2019-02-04 15:17:13Z

4

It seems that item.ruta is empty, so no route could be generated.

You could specifiy a fallback like this {{ path(item.ruta ? item.ruta : 'new') }} or if you want to stay on the current page you need to do something like descripted here: get current url in twig template?

{% if item.ruta %}
    href="{{ path(item.ruta) }}"
{% else %}
    href="{{ path(app.request.attributes.get('_route'), app.request.attributes.get('_route_params')) }}"
{% endif %}

or if you really want # only, then remove the path function call

{% if item.ruta %}
    href="{{ path(item.ruta) }}"
{% else %}
    href="#"
{% endif %}

answered Feb 4, 2019 at 15:17

Fabian Schmick

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1 Comment

DarkBee Over a year ago

<a href="{{ item.ruta ? item.ruta : '#' }}">...</a>

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