Regex to match the string which contains dot

Question

I have a following regex:

[.][a-zA-Z]

So, if there's a string like .row then it will select .r. What I want is to be able to select only the dot i.e. regex selects only the dot(.)!

Without more details: what part of capture group 2 in ((\.)][a-zA-Z]+) does not address this need? And more importantly, what are you actually trying to do, because just "finding the dot" in something like .row cannot possibly be the end of what you want to do. What are you trying to do that requires finding that dot? — Mike 'Pomax' Kamermans
– Mike 'Pomax' Kamermans, Commented Feb 12, 2019 at 6:07

Code Maniac · Accepted Answer · 2019-02-12 06:06:39Z

2

let str  = `.row`

console.log(str.match(/\.(?=[A-Za-z])/g))

answered Feb 12, 2019 at 6:01

Code Maniac

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4 Comments

@Sanjay sorry it was a typo. fixed

I tried this([\.][(?=[A-Za-z])]/g) in VSCode find and replace. It didn't work

@Sanjay why are you putting positive lookahead in character class. use this /\.(?=[A-Za-z])/

Solomon Tam · Accepted Answer · 2019-02-12 06:05:45Z

0

If you want to just select the dot, escape your . with \. since . means any single character. And don't include [a-zA-Z]

[\.]

answered Feb 12, 2019 at 6:04

Solomon Tam

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It will select the number too then

What number?? Please at least try to give us your input and expected output.