I need help to make sure that all numbers in my array are displayed because only the first 2 are being displayed.
function tizer(n) {
var firstArray = (""+n).split('');
var newArray = [];
for (var i = 0; i < firstArray.length; i++) {
newArray[i] = parseInt(firstArray.shift(),10);
}
return newArray;
}
console.log(tizer(8675));
Result: [8,6]
Expected: [8,6,7,5]
It is much simpler than you thought. You should have used firstArray[i] instead of firstArray.shift().
function tizer(n) {
var firstArray = (""+n).split('');
var newArray = [];
for (var i = 0; i < firstArray.length; i++) {
newArray[i] = parseInt(firstArray[i],10);
}
// Sort odd first
var arraySorted = [...newArray.filter(item => item%2 == 1), ...newArray.filter(item => item%2 == 0)]
return arraySorted;
}
console.log(tizer(8675));
Simply use a .map(Number) after you .split
function tizer(n) {
return (n + '').split('').map(Number);
}
console.log(tizer(8675));