Java : RegEx to find a substring Collection

Question

I am using below java program to find list of js files as a Substring.

    String str = "jsLib//connect.facebook.net/en_US/fbevents.js , jsLib//connect.facebook.net/en_US/fbevents2.js;";
    String patternStr = "(\\/.*?\\.js)";
    Pattern pattern = Pattern.compile(patternStr);
    Matcher matcher = pattern.matcher(html);
    if (matcher.find()) {
        System.out.println("Count:" + matcher.groupCount());
        jsLib = matcher.group(1);
        jsLib = jsLib.substring(jsLib.lastIndexOf('/') + 1, jsLib.length());
        System.out.println("jsLib:" + jsLib);
    }

Regex : I used String patternStr="(\\/.*?\\.js)";

Expected Result : both fbevents.js and fbevents2.js should be matched and part of result

Actual Result : only fbevents.js is matched

Wiktor Stribiżew · Accepted Answer · 2019-02-17 22:29:43Z

3

You may get all your results using while loop and a regex like [^/]*\.js:

String str = "jsLib//connect.facebook.net/en_US/fbevents.js , jsLib//connect.facebook.net/en_US/fbevents2.js;";
String patternStr = "[^/]*\\.js";
Pattern pattern = Pattern.compile(patternStr);
Matcher matcher = pattern.matcher(str);
while (matcher.find()) {
    System.out.println("jsLib:" + matcher.group());
}

Output:

jsLib:fbevents.js
jsLib:fbevents2.js

See the Java demo and the regex demo.

The [^/]*\.js pattern matches any 0+ chars other than / (with [^/]*) and then a .js substring.

answered Feb 17, 2019 at 22:29

Wiktor Stribiżew

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