Dead simple cross-domain php script

Question

I'm looking for a simple script in which I can do something like this

$.getScript('fetcher.php?url=' + escape('http://www.google.com') + '&callback=console.log');

The response should be one really long line that looks like this:

console.log({responseText: '<!doctype html><html><head><meta http-equiv="content-type" content="text/html; charset=UTF-8"><title>Google</title><script>windo...'})

It shouldn't be more than 10 lines of code and there's no way it doesn't already exist.

I'm using php in XAMPP and am just using it to build a database so I don't need any frills included (no get vs post, no data included) just file_get_contents and $_GET. Of course I would still like to encoded the url

Do you limit the characters per line? If dont, I can write it in 1 line :D — thaolt
– thaolt, Commented Mar 31, 2011 at 2:39
@thaolt: How about a readable script, just not too intense of the options — qwertymk
– qwertymk, Commented Mar 31, 2011 at 2:41
@SeanKinsey: I was asking because I assumed this already existed and didn't want to reinvent the wheel — qwertymk
– qwertymk, Commented Mar 31, 2011 at 12:06

thaolt · Accepted Answer · 2011-03-31 03:21:11Z

1

How about this , updated

<?php
    // fetcher.php
    $url = $_GET['url'];
    $callback = $_GET['callback'];
    $read = file_get_contents($url);
    $read = addslashes(htmlspecialchars(str_replace("\n","\\n",$read)));
?>
<script>
    <?php echo $callback ?>({responseText: '<?php echo $read; ?>'});
</script>

edited Mar 31, 2011 at 3:21

answered Mar 31, 2011 at 2:51

thaolt

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5 Comments

qwertymk Over a year ago

I want to preserve '\n'(linebreaks in the html) to become '\\n' (in the response) so that in the string it's a newline. Also I wan to be able to use escaped url

thaolt Over a year ago

I didnt test this yet, did you try the code of dakis, Ill test it out

qwertymk Over a year ago

I didn't bother, I don't have curl

thaolt Over a year ago

ok, ill try to help you out,str_replace("\n","\\n".. seems doesnt work

thaolt Over a year ago

it run ok now, but I dont know if it fits your need

Daniel · Accepted Answer · 2011-03-31 02:52:34Z

0

fetcher.php

<?php
    $ch = curl_init();
    curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
    curl_setopt($ch, CURLOPT_URL, $_GET['url']);
    echo curl_exec($ch);
    curl_close($ch);
?>

javascript

$.get("fetcher.php", {url: "http://www.google.com/"}, function(response) {
    console.log(response);
});

answered Mar 31, 2011 at 2:52

Daniel

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