TypeError: 'StringVar' object is not iterable

Question

from tkinter import*
raiz=Tk()
raiz.title("Last Recently Used LRU")
raiz.resizable(1,1)
raiz.geometry("1080x720")
#-----------------------------------------
marcos=IntVar()
#-------------------------------------
label1=Label(raiz,text="Numero de Marcos:")
label1.place(x=260,y=100)
texto1=Entry(raiz,textvariable=marcos)
texto1.place(x=500,y=100)
s=StringVar()
label2_5=Label(raiz,text="*Introduce una cadena de numeros separados por espacios")
label2_5.place(x=260,y=200)
label2=Label(raiz,text="Cadena de Referencias:")
label2.place(x=260,y=250)
texto2=Entry(raiz,textvariable=s)
texto2.place(x=555,y=250)
def perro():
    PROC=IntVar()
    PROC = int(input())
    f, st, fallos, mf = [], [], 0, 'No'
    s = list(map(int, input().strip().split()))
for i in s:
    if i not in f:
        if len(f)<PROC:
            f.append(i)
            st.append(len(f)-1)
        else:
            ind = st.pop(0)
            f[ind] = i
            st.append(ind)
        mf = 'X'
        fallos += 1
    else:
        st.append(st.pop(st.index(f.index(i))))
    mf = '--'
    print("\n\n")
    print("   %d\t\t" % i, end='')
    for x in f:
        print(x, end=' ')
    for x in range(PROC - len(f)):
        print(' ', end=' ')
    print(" %s" % mf)
botonp=Button(raiz,text="Ejecutar",command=perro)


botonp.place(x=540,y=350)
raiz.mainloop()

line 33, in for i in s: TypeError: 'StringVar' object is not iterable

Ok here is the full code, i try to make a GUI with Tkinter but there's a problem, i don't know what to do with this error.

Any ideas how to fix?

Check the indent of line if i not in f: just after the line for i in s: If this is a typo in your post please edit it. Otherwise fix your code. — Aida
– Aida, Commented Mar 1, 2019 at 18:27

blhsing · Accepted Answer · 2019-03-01 19:16:53Z

1

The name s is defined as a global variable of type StringVar with the statement:

s=StringVar()

so when you attempt to iterate over it with:

for i in s:

it produces the said exception since your StringVar object is not iterable.

The fact that you assigned s with a list inside the function perro does not help because the s variable that is assigned with a list is local to the perro function and is not at all the same s as the global variable.

You should make perro return the list and iterate over the returning value instead.

Change:

    s = list(map(int, input().strip().split()))
for i in s:

to:

    return list(map(int, input().strip().split()))
for i in perro():

edited Mar 1, 2019 at 19:16

answered Mar 1, 2019 at 18:04

blhsing

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3 Comments

m13op22 Over a year ago

Where is there a variable called list in his code?

blhsing Over a year ago

It's in "some other parts" of the OP's code as I mentioned. The OP did not post the code is full but it is certain that list has been assigned with other values in other parts of the code that are not posted here.

blhsing Over a year ago

@GerardoSoto I've updated my answer accordingly then.

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