Get value of enum type in swift

Question

I'm trying to get a default value for the enum so I can use it as a param. This code isn't working, but I'd like to get something like:

print("Param: \(Params.RCLoss.description)")

and the output should be:

Param: RC_LOSS_MAN

Here is the code:

enum Params {
  enum RCLoss: Int32, CustomStringConvertible {
    case disable = 0
    case enable = 1

    var description: String {
        return "RC_LOSS_MAN"
    }
  } 
}

I want to be able to pass this:

set(parameterType: Params.RCLoss.description, parameterValue: Params.RCLoss.enable)

which should correspond to these values being set:

set(parameterType: "RC_LOSS_MAN", parameterValue: 0)

.rawValue should return you the Int32. Swift Guide: "You access the raw value of an enumeration case with its rawValue property." — keji
– keji, Commented Mar 5, 2019 at 21:40
Possible duplicate of What is the use of "static" keyword if "let" keyword used to define constants/immutables in swift? — John Montgomery
– John Montgomery, Commented Mar 5, 2019 at 21:57
It is Swift naming convention to name all your enumeration types starting with an uppercase letter enum RCLoss — Leo Dabus
– Leo Dabus, Commented Mar 5, 2019 at 21:59

Sulthan · Accepted Answer · 2019-03-05 22:13:24Z

1

It seems you want just

enum rcLoss: Int32 {
  case disable = 0
  case enable = 1 

  static var description: String {
    return "RC_LOSS_MAN"
  }
}

rcLoss is a type, description has to be static for you to be able to call rcLoss.description. And that means you cannot use CustomStringConvertible. You would use CustomStringConvertible to convert enum values to a String.

answered Mar 5, 2019 at 22:13

Sulthan

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1 Comment

Douglas Silva Over a year ago

That's it! Thank you so much!

keji · Accepted Answer · 2019-03-05 21:47:13Z

0

From Swift Book - Enumerations:

You access the raw value of an enumeration case with its rawValue property.

set(parameterType: Params.rcLoss.description, parameterValue: Params.rcLoss.enable.rawValue)

If you can though I would use the enumeration as the type of the formal parameter so that someone can't pass an invalid value to that function. Also I'm assuming that there is a reason you have nested an enum inside of an otherwise empty enum...

answered Mar 5, 2019 at 21:47

keji

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1 Comment

John Montgomery Over a year ago

Given the name "Params," I suspect they're using the outer enum as a poor man's namespace (and there are other properties that aren't relevant to the question).

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