Website
myList = ['Artik']
How can I check if content of myList is visible in website above?
<span class="ipo-TeamStack_TeamWrapper">Artik<span>
This is the webelement holding 'Artik' in the website.
My goal is to click the element containing 'Artik' and do some stuff after that.
This is how you find an element by xpath in selenium. I am using Firefox here but you can use Chrome as well.
from selenium import webdriver
myList = ['Artik']
driver = webdriver.Firefox() # or .Chrome()
driver.get('www.theWebsite.com')
current = driver.find_element_by_xpath('//span[@class="ipo-TeamStack_TeamWrapper"]').text
if current in myList:
print('YAY')
driver.quit()
driver.find_elements_by_xpath("//*[contains(text(), 'Artik')]")
this return WebElement list contain 'Artik'.
parameter(like 'Artik') is case sensitive.
if you are convinced 'Artik' is only one,
driver.find_element_by_xpath("//*[contains(text(), 'Artik')]").click()
this will find WebElement with 'Artik' and click.
driver.find_element_by_xpath("//*[contains(text(), 'Artik')]").click() works well. <br/>What if I wanted to use text from myList[0] instead of 'Artik'?<br/>driver.find_element_by_xpath('//*[contains(text(), myList[0])]').click()<br/>Will cause error.driver.find_element_by_xpath('//*[contains(text(), myList[0])]').click() does not cause error like I told above, but it does not click the correct element so it is not useful.