Pass current URL php in form using post

Question

I have php file with html coding inside. I'm using include statement to import the same form into many different pages, however I need to know which page the form was submitted from. Files themselves are .php, however the most of coding is in html. How can I add the current URL of the website the form was submitted from? I use post method.

<form action="post.php" method="post">
   <input type="hidden" name="url" value="(Current URL here)" />
   <input type="text" id="email" name="email">
</form>

and php part:

<?php
  $addressto = "[email protected]";
  $subject = "Message";
  $content = "Email: ".$_POST['email']."\n"
            ."URL: ".$_POST['url']."\n";

    $email = $_POST['email'];
    if (mail($addressto, $subject, $content, 'From: <' . $email . '>')) {
        header("Location: message-sent.html");
    }
?>

I believe I need some sort of code that gets URL. I found few similar questions here but none of them clearly explains how to do it. Thank you for your help.

<input type="hidden" name="url" value="<?php echo $_SERVER['PHP_SELF']; ?>" /> should work — user10051234
– user10051234, Commented Mar 10, 2019 at 21:15

user11171256 · Accepted Answer · 2019-03-10 21:19:12Z

2

<?php
$actual_link = "http://$_SERVER[HTTP_HOST]$_SERVER[REQUEST_URI]";

?>

<form action="post.php" method="post">
   <input type="hidden" name="url" value="<?=$actual_link?>" />
   <input type="text" id="email" name="email">
</form>

answered Mar 10, 2019 at 21:19

user11171256

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Comments

Jack Templeman · Accepted Answer · 2019-03-10 21:15:35Z

1

Take a look at the answer and code below

Get the full URL in PHP

<form action="post.php" method="post">
  <input type="hidden" name="url" value="<?php echo "http://$_SERVER[HTTP_HOST]$_SERVER[REQUEST_URI]"; ?>" />
  <input type="text" id="email" name="email">
</form>

answered Mar 10, 2019 at 21:15

Jack Templeman

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Comments

ArtisticPhoenix · Accepted Answer · 2019-03-10 22:37:44Z

0

Passing a link is a bit point less $_SERVER[HTTP_REFERRER] will generally work,

It's subject to client modification but so are form fields. I would check the domain on the back end just to be safe if you really want to.

HTTP_REFERRER - is the address making the request, so in your case it should be the page with the form.

One less variable to handle.

  $content = "Email: ".$_POST['email']."\n"
        ."URL: ".$_SERVER[HTTP_REFERRER]."\n";


 $email = $_POST['email'];
 if (mail($addressto, $subject, $content, 'From: <' . $email . '>')) {
    header("Location: message-sent.html");
 }

Cheers!

edited Mar 10, 2019 at 22:37

answered Mar 10, 2019 at 22:30

ArtisticPhoenix

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