1

My variable L1 looks this:

[{'distance': 1.9999,
  'breakEvenDistance': 1.9329,
  'max': 0.0010342833053929787},
 {'distance': 1.9251,
  'breakEvenDistance': 2.0669999999999997,
  'max': 0.0011183923895419084,
  'min': 0.0010342833053929787},
 {'distance': 1.8802,
  'breakEvenDistance': 1.6758,
  'max': 0.0011927892918825562,
  'min': 0.0011183923895419084},
 {'distance': 1.8802,
  'breakEvenDistance': 1.5956,
  'max': 0.0012522046577102665,
  'min': 0.0011927892918825562}]

What I need is to remove the last 'max' in my list! I tried to check the doc, used the function del on L1[-1]['max'] but did not work.. any idea or clue? thanks!

4
  • 3
    Can't reproduce, works just fine. Commented Mar 12, 2019 at 11:38
  • 2
    works just fine del L1[-1]['max'] does the job Commented Mar 12, 2019 at 11:39
  • Do you want to remove max key from every element? deleting last dict max just works fine using del L1[-1]['max'] Commented Mar 12, 2019 at 11:43
  • @viktor.w it's unclear whether you want to remove the max key from the last dict, or the last dict entirely, or something else. If the first, you've had answers. If the second, you can use lst.pop() or del lst[-1] to remove the last element. If otherwise, you'll need to clarify. Commented Mar 12, 2019 at 11:45

1 Answer 1

3

-1 to get the last element of the dict:

del dict_[-1]['max']
print(dict_)

OUTPUT:

[
 {'distance': 1.9999, 'breakEvenDistance': 1.9329, 'max': 0.0010342833053929787},
 {'distance': 1.9251, 'breakEvenDistance': 2.0669999999999997, 'max': 0.0011183923895419084, 
  'min': 0.0010342833053929787}, 
 {'distance': 1.8802, 'breakEvenDistance': 1.6758, 'max': 0.0011927892918825562, 
  'min': 0.0011183923895419084}, 
 {'distance': 1.8802, 'breakEvenDistance': 1.5956, 
  'min': 0.0011927892918825562}
]
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1 Comment

This is already tried by OP and already commented by @rachidelkedmiri.

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