How to remove url starting with www.*** from a string using regex?

Question

I am trying to filter out all URL from a string input. Currently, I have a regex that is able to find URLs starting with http:// or https:// or ftp:// as seen below:

var _input = document.querySelector("#input");
var btn = document.querySelector("#btn");
var results = document.querySelector("#results");

btn.addEventListener("click", function() {
var input_ = _input.value;
var cleanInput = input_.replace(/(?:https?|ftp):\/\/[\n\S]+/g, '');
results.innerHTML = cleanInput;
});

<textarea id="input" rows="5" style="width: 200px;"></textarea>
<button id="btn">SUBMIT</button>
<div id="results"></div>

What Regex should I use to match www.*** and also it should not case sensitive. http or HTTP should also be match.

Try .replace(/(?:(?:http|ftp)s?:\/\/|www\.)[\n\S]+/ig, ''); — Wiktor Stribiżew
– Wiktor Stribiżew, Commented Mar 19, 2019 at 9:59
Have you tried to create the regex that you are looking for yourself? If not, you should do that; if so, could you share what you've tried in your question? It helps to show you've put effort into figuring out the problem yourself, and gives answerers a starting point to really help your understanding, rather than to just give you a regular expression that works. — Nebula
– Nebula, Commented Mar 19, 2019 at 10:04

Wiktor Stribiżew · Accepted Answer · 2019-03-19 10:08:22Z

2

You may adjust your regex to

.replace(/(?:(?:http|ftp)s?:\/\/|www\.)[\n\S]+/ig, '');

Details

ig - ignore case (i) and global (g) modifiers to match all occurrences in a case insensitive way
(?:(?:http|ftp)s?:\/\/|www\.) - https://, http://, ftp://, ftps:// or www.
[\n\S]+ - 1 or more non-whitespace or LF chars

answered Mar 19, 2019 at 10:08

Wiktor Stribiżew

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2 Comments

r3dst0rm Over a year ago

Nice solution. Interesting that you did respect non-whitespace and LF chars. Thumbs up for that

Wiktor Stribiżew Over a year ago

@r3dst0rm It is just the same as OP regex, I only added required fixes.

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