How can I JSON parse this into a JSON object?

Question

I pass a $input.json('$') body from the apigateway which is x-application/urlencoded to a Lambda function and insert into a Dynamodb. The event.body is like this

event.body

How can I unescape this string and get the JSON object? I've tried JSON.parse() and something like .replace slashes but it didn't work.

use Json.parse () twice.

rohitwtbs
– rohitwtbs

2019-03-25 08:46:24 +00:00
Commented Mar 25, 2019 at 8:46 — rohitwtbs
– rohitwtbs, Commented Mar 25, 2019 at 8:46

dege · Accepted Answer · 2019-03-25 09:17:51Z

3

You can use the $util.parseJson()

EDIT: Example:

#set ($bodyObj = $util.parseJson($input.body))

then use it :

{ 
    "TableName": "Mytable",
    "Item": {
    "commentId": {
            "S": "$context.requestId"
            },
        "pageId": {
            "S": "bodyObj.pageId"
            },
        "userName": {
            "S": "bodyObj.userName)"
        },
        "message": {
            "S": bodyObj.message"
        }
    }
}

example modified from https://aws.amazon.com/blogs/compute/amazon-api-gateway-mapping-improvements/

also might be worth checking the https://aws.amazon.com/blogs/compute/using-amazon-api-gateway-as-a-proxy-for-dynamodb/

edited Mar 25, 2019 at 9:17

answered Mar 24, 2019 at 12:07

dege

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2 Comments

jeffdeng Over a year ago

sorry, but,how do you write in the template?I am tring "body": $util.parseJson($input.body),but get the could not parse json response.

dege Over a year ago

Edited the answer with extra examples

sc0rp1on · Accepted Answer · 2019-03-24 21:51:36Z

0

I use the json.loads and json.dump functions. And I get the same kind of string in DynamoDB whenever I store something

answered Mar 24, 2019 at 21:51

sc0rp1on

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