Regex to validate an alphanumeric consecutive string

Question

I'm looking to have a regex that validates any string from 046R to 120R.

Sounds simple enough, but I'm missing something here. this is what I have:

^04[6-9]R|0[5-9][0-9]R|10[0-9]R|11[0-9]R|120R +$

But it's not picking up the 120R as a valid string as well. As can this expression be simplified?

Thanks in advance.

Why do you have ` +` (only) after 120R? It means that when you have 120R, it has to be followed by at least one space. — sawa
– sawa, Commented Apr 3, 2011 at 21:13

kennytm · Accepted Answer · 2011-04-04 05:18:23Z

2

Remove the final +. Otherwise it requires one or more space after the string 120R to be validated.

Also, | has very low precedence. The ^ and $ should stay outside of the group containing |.

^(?:04[6-9]|0[5-9][0-9]|1[01][0-9]|120)R\s*$

edited Apr 4, 2011 at 5:18

answered Apr 3, 2011 at 21:12

kennytm

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3 Comments

Xavier Holt Over a year ago

Beat me to it. One more thing, though - if you do want to allow trailing spaces, you can use * (zero or more) instead of + (one or more): ^(...)R *$ Cheers!

Bruno Over a year ago

That's not working out. It doesn't accept some of the values that it should. Have a look: [link]rubular.com/r/YZsPIRInNV

kennytm Over a year ago

@Bruno: That's because your test case is not "clean" — some entries contains unnecessary trailing space. This can be fixed by adding a \s* at the end like Xavier's comment. See rubular.com/r/3prIDsOncr

sawa · Accepted Answer · 2011-04-03 21:42:16Z

1

You can exclude certain matches by using negative lookahead, and simplify the regex.

^(?!0[0-3])(?!04[0-5])[01]\d\dR$

edited Apr 3, 2011 at 21:42

answered Apr 3, 2011 at 21:20

sawa

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