parse xml children with multiple children with same name, python

Question

I have xml:

<tree-root>
<sub1>it is sub1</sub1>
    <sub2>
    <sub3>sub3</sub3>
    <position>5584</position>
    <source-IP>
    <address-IP>2.104.54.11</address-IP>
    <address-IP>172.16.33.11</address-IP>
   </source-IP>
</sub2>

I would like to parse all the children inside of source-IP. The output shall be both IPs not just one. I would like to have :

2.104.54.11
172.16.33.11

It is similar to Parse XML with Python when multiple children share a name, but I would kindly ask for all the code.

Thank you in advance.

I have tried print(tree.find('sub2').find('source-IP').findall('address-IP').text);, but only bringing the error:

'list' object has no attribute 'text'

Here is the full code:

print(tree.find('sub2').find('source-IP').find('address-IP').text)

{    import xml.etree.ElementTree as ET  
tree = ET.parse('IPs.xml')  
root = tree.getroot()


print(root.text)
print(tree.find('sub1').text)                         
print(tree.find('sub2').find('sub3').text)  
print(tree.find('sub2').find('position').text)
 print('I would like to print all the IPs below, not just the first one')
print(tree.find('sub2').find('source-IP').find('address-IP').text)
print(tree.find('sub2').find('source-IP').find('address-IP').text)
}

John Gordon · Accepted Answer · 2019-03-24 20:18:03Z

1

.findall() returns a list of items. You need to loop over each of those items to get the text:

for address_ip in tree.find('sub2').find('source-IP').findall('address-IP'):
    print address_ip.text

answered Mar 24, 2019 at 20:18

John Gordon

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