I have a list whose contents are:
x = ['A', 2, 'B', 2, 'C', 2, 'D', 2, 'a', 4, 'b', 2, 'c', 1, 'd', 2]
I want the output as:
A2B2C2D2a4b2c1d2
I tried with the line:
print(''.join(str(x)))
But it gives me an error that says:
print(''.join(str(x)))
TypeError: 'str' object is not callable`
Guess it's occurring because of those integers along with the strings.
How to tackle this to get the desired output as mentioned above?
str(x) gives the string representation of x - it doesn't iterate over the values in x. Try this:
print(''.join([str(a) for a in x]))
Try this :
print(''.join([str(k) for k in x]))
OUTPUT :
A2B2C2D2a4b2c1d2
x = ['A', 2, 'B', 2, 'C', 2, 'D', 2, 'a', 4, 'b', 2, 'c', 1, 'd', 2]
For understanding:
s = '' # empty var
for elem in x: # for each elem in x
s += str(elem) # concatenate it with prev s
print(s) # A2B2C2D2a4b2c1d2
Which can be shorten to:
print(''.join([str(elem) for elem in x])) # A2B2C2D2a4b2c1d2
Using reduce:
print(reduce(lambda x,y:str(x)+str(y),x)) # A2B2C2D2a4b2c1d2
It can also be done by making a new list where all the elements from x have been converted to strings:
x = ['A', 2, 'B', 2, 'C', 2, 'D', 2, 'a', 4, 'b', 2, 'c', 1, 'd', 2]
strings = []
for e in x:
strings.append(str(e))
print(''.join(strings))
The above answers are much cleaner though.
print(''.join(map(str, x)))