Javascript: exclude from regex in replace

Question

In this regex:

let str = "hello 〔world〕，foo、bar。";
str.replace(/(〔(.*?)〕|(、)|(，)|(。))/gi,'<div>$1</div>');

How to exclude these two square brackets "〔" and "〕" from the result ?

In order to get this result:

"hello <div>world</div><div>，</div>foo<div>、</div>bar<div>。</div>"

I would call the replace method 2 times. One for replacing the unwanted chars with nothing. — Ram
– Ram, Commented Apr 6, 2019 at 3:23
@undefined why not use the callback function of replace instead of calling it twice, i will go for callback function of replace as we can save extra work — Code Maniac
– Code Maniac, Commented Apr 6, 2019 at 3:28

Code Maniac · Accepted Answer · 2019-04-06 03:32:15Z

1

Instead of using a single group you can use two groups. and in callback based on group you can return the value accordingly

let str = "hello 〔world〕，foo、bar。";
str = str.replace(/〔(.*?)〕|((…)|(。)|(，)|(、))/gi,(match,g1,g2)=>`<div>${g1 ? g1 : g2}</div>`);

console.log(str)

answered Apr 6, 2019 at 3:22

Code Maniac

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