I am trying to get the absolute path of working directory, and pass it to a method. I am getting the path in the form
C:\eclipse\workspace\file.txt
but eclipse must receive it in the form:
C:\\eclipse\\workspace\\file.txt
So I am doing a replace, but it works only for one char, how to modify it?
String path = new File("").getAbsolutePath();
path = path.replace( '\\', '\\\\' );
something = method.read(path+"\\file.txt");
Change this:
path = path.replace( '\\', '\\\\' );
To this:
path = path.replaceAll( "\\", "\\\\" );
try using the replaceAll method.
Just use double quotes to represent more than one char. It's then called a String.
path = path.replace("\\", "\\\\");
Note that this requires a minimum of Java 1.5 to work.
You should use:
public String replaceAll(String regex,
String replacement)
Replaces each substring of this string that matches the given regular expression with the given replacement.
If you just want the current working directory, the simplest approach is this:
String currentdir = System.getProperty("user.dir");
you can use path = path.replaceAll( '\\', '/' ); it works
Not sure if this will help.. I ran into the same issue with the application I am building.
In my app, I basically use JFileChooser to graphically select the file I want. Long story short, the absolute path of the selected file comes back as "C:\Documents and Settings....\xCBL.xml"
The path was then passed to another class for manipulation, however it failed because of the single '\'. The fix -
String absPath = file.getAbsolutePath();
System.out.println("File Path:"+absPath);
String filePath = absPath.replaceAll("\\\\", "\\\\\\\\");
System.out.println("New File Path:"+filePath);
Output:
File Path:C:\Documents and Settings\tanzim.hasan\workspace\XML to Java\xcbl.XML
New File Path:C:\\Documents and Settings\\tanzim.hasan\\workspace\\XML to Java\\xcbl.XML
Hope the above helps.
