Way converting char array into NSString object with one more in the end character

Question

code:

const char sbyte[] = {65, 66};

NSLog(@"byte：%c", 66);
NSLog(@"byte：%c", 67);
NSLog(@"byte：%s", sbyte);

NSString *string1 = [[NSString alloc] initWithCString:sbyte encoding:NSUTF8StringEncoding];
NSLog(@"string1: %@", string1);

NSString *string2 = [NSString stringWithFormat:@"%s", sbyte];
NSLog(@"string2: %@", string2);

print:

 byte：B
 byte：C
 byte：ABb
 string1: ABb
 string2: ABb

The correct application is 'AB', but now it is 'ABb', one more character 'b'??

thanks!

Sulthan · Accepted Answer · 2019-04-15 13:13:32Z

3

All C strings have to be zero terminated:

const char sbyte[] = {65, 66, 0};

They don't contain any length information therefore the zero is a way to detect end of data.

answered Apr 15, 2019 at 13:13

Sulthan

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iHTCboy Over a year ago

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