What do I return to the main function from my string function?

Question

I finished my lab problem, but I have a quick question to fix the end. I have a vector in the function that needs to be returned to main so I can output the elements of the vector. I put return a; at the end of the function since a is the name of the vector in the function but I'm getting an error.

*Where it says "cout << the names are " should be in the main but I can't figure out what to put in the return. *I also put return 0 because it was the only way I had the whole program working since the output is also in the function, but I need it back in main and change the return 0; Sorry if this is a bad question I'm still learning, thanks.

string switching(vector<string> a, int n) {
    for (int i = 0; i < n - 1; i++) {
        for (int j = i + 1; j < n; j++) {
            if (a[i] > a[j]) {
                swap(a[i], a[j]);
            }
        }
    }

    cout << "The order of names are...\n";
    for (int i = 0; i < n; i++) {
        cout << a[i] << "\n";
    }

    return 0;
}

You could change the signature to return a vector<string> instead then return a; would work. — drescherjm
– drescherjm, Commented Apr 26, 2019 at 2:40
You return the thing that you want to return. return a; gives you an error because a is vector<string> but you put the return type as string. How would you fix that? — Stack Exchange Broke The Law
– Stack Exchange Broke The Law, Commented Apr 26, 2019 at 2:47

Gardener · Accepted Answer · 2019-04-26 02:59:52Z

1

As has been suggested, you can change the function signature to

std::vector<std::string> switching(std::vector<std::string> a, int n)

Or, you could pass the string vector argument by reference:

void switching(std::vector<std::string>& a, int n)

This shows a main calling the first version:

#include <iostream>
#include <string>
#include <vector>

std::vector<std::string> switching(std::vector<std::string> a, int n) {
  for (int i = 0; i < n - 1; i++) {
    for (int j = i + 1; j < n; j++) {
      if (a[i] > a[j]) {
        swap(a[i], a[j]);
      }
    }
  }
  return a;
}

int main()
{
  std::vector<std::string> strings{
    "John",
    "Fred",
    "Alice"
  };

  auto sorted = switching(strings, strings.size());
  std::cout << "The order of names are...\n";
  for (auto const& name : sorted) {
    std::cout << name << "\n";
  }

  return 0;
}

answered Apr 26, 2019 at 2:59

Gardener

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5 Comments

Patrick Over a year ago

Thank you so much for the help, I appreciate your time helping me

Patrick Over a year ago

Also quick question, my lab HW was to get a list of names up to 20 max and return them in alphabetical order, do you think I should change it from vectors to dynamic arrays or Vectors are fine? Thanks again!

Gardener Over a year ago

Vectors are dynamic arrays. You may be able to stick with the vectors, You will have to guage that.

Gardener Over a year ago

If the answer works for you, go ahead and accept it. Let me know if you have any further questions.

Patrick Over a year ago

yes just accepted, I forgot to do it yesterday. sorry about that

wushuomin · Accepted Answer · 2019-04-26 03:01:12Z

0

1.You could modify the return type of the function;

   vector<string> switching(vector<string> a, int n)
{
     //Your core-code here;
     return a;    
}

The parameters could be pass by reference.

void switching(vector<string> &a, int n)
{
     //Your core-code here;

}

In this way, the parameters could change simultaneously in main function.

answered Apr 26, 2019 at 3:01

wushuomin

1

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