Push second array inside first array

Question

I have two array containing some value.

$type = array("first", "second", "third");

$date = array(
          0 => "2019-04-30",
          1 => "2019-05-01",
          2 => "2019-05-02",
          3 => "2019-05-03"
        );

I need output something like this:

[
    type :first, 
    date: [
        "2019-04-30": 1.2,
        .....
    ]

]

But for some reason I am not getting in that format.

This is the code I have tried.

$newArr = array();

foreach($type as $tt) {
    $newArr[]['type'] = $tt;
    $newDate = array();
    foreach ($date as $d) {
        $newDate[$d] = 1.2;
    }
    $newArr[]['date'] = $newDate;
}

Can anybody show what I did mistake.

Thank You.

Nigel Ren · Accepted Answer · 2019-04-29 07:07:03Z

3

It just comes down to building the array and then adding it in the right order, this builds all of the data and adds it in one go at the end of the loop...

$newArr = array();

foreach($type as $tt) {
    $newDate = array();
    foreach ($date as $d) {
        $newDate[$d] = 1.2;
    }
    $newArr[] = [ 'type' => $tt, 'date' => $newDate];
}

You could shorten it to this, but it doesn't really make much difference...

foreach($type as $tt) {
    $newArr[] = [ 'type' => $tt, 'date' => array_fill_keys($date, 1.2)];
}

edited Apr 29, 2019 at 7:07

answered Apr 29, 2019 at 7:01

Nigel Ren

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2 Comments

S S Over a year ago

I have to do some calculation to each date so shorten one might not work . I need to sum the value

Nigel Ren Over a year ago

That is why I left the original code there, sometimes things aren't as simple as the code posted in the question.

Varun Malhotra · Accepted Answer · 2019-04-29 07:08:54Z

0

Lets make it more simple

$newArr = array();
$newdates = array();
  foreach($dates as $date){
  $newdates[$date] = 1.2;
}

    foreach($type as $tt) {
        $newArry[] = array("type"=>$tt,"date"=>$newdates);
    }

edited Apr 29, 2019 at 7:08

answered Apr 29, 2019 at 7:04

Varun Malhotra

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1 Comment

Nigel Ren Over a year ago

$date isn't in the format of the data they are asking for.

Rakesh Jakhar · Accepted Answer · 2019-04-29 09:07:06Z

0

You can use array_map and array_fill_keys for the desired result

 $type = ["first", "second", "third"];
 $date = [
      0 => "2019-04-30",
      1 => "2019-05-01",
      2 => "2019-05-02",
      3 => "2019-05-03"
    ];
$newArr = [];
array_map(function($t, $d) use ($date, &$newArr){
  $newArr[] = [
    'type' => $t,
    'date' => array_fill_keys($date, 1.2)
  ];
}, $type, $date);

answered Apr 29, 2019 at 9:07

Rakesh Jakhar

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