Why does PyArg_ParseTuple always return false?

Question

My PyFLoat_ParseTuple call always return false, with correct call from python side.

I am working on wrapping my C++ for Python and using python extension. I had a successful project, and generating the current one based on that.
I always had a crash in my python run, and during the investigation I reduced my code to the following minim code to repeat it.

If I change both C++/Python side to non-arg call, it works as expected. But the "Parse error" is always printed when I passed in args.

C++:

static PyObject *myfunc(PyObject *self, PyObject *args)
{
    float v[6];
    if (!PyArg_ParseTuple(args, "ffffff", v,v+1,v+2,v+3,v+4,v+5));
    { 
                //I can alway see this prited.
        cerr<<"Parse error\n";
        return NULL;
    }
        return PyString_FromFormat("No error!\n");
}

Python:

print func(0.1,0.2,0.3,0.4,0.5,0.6)

Dmitry · Accepted Answer · 2019-05-02 18:03:10Z

1

a very simple typo:

if (!PyArg_ParseTuple(args, "ffffff", v,v+1,v+2,v+3,v+4,v+5));

- see the semicolon ; at the end of if?

answered May 2, 2019 at 18:03

Dmitry

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