How to store xpath in variable and use it with XSLT 1.0

Question

I am trying to use a variable that has xpath in for-each. But it is giving me an error that Expression must evaluate to a node-set.

NodeName is defined as

<xsl:variable name="NodeName" select="name(.)"/>

<xsl:variable name="SyncPath" 
              select="concat('/combinedxml/com.csc_PolicySyncRs/',$NodeName)"/>

and here is for-each loop

<xsl:for-each select="$SyncPath/*">

Could you please provide nicely-formatted XSLT fragment you're referring to? — oiavorskyi
– oiavorskyi, Commented Apr 8, 2011 at 14:51
This is a duplicate of stackoverflow.com/questions/4377811/using-dynamic-xpath-in-xslt or stackoverflow.com/questions/4682151/… or stackoverflow.com/questions/1551526/… or one of google.com/search?q=site%3Astackoverflow.com+xslt+dynamic+xpath — user357812
– user357812, Commented Apr 8, 2011 at 15:10
For this case use: <xsl:variable name="SyncPath" select="/combinedxml/com.csc_PolicySyncRs/*[name()=$NodeName]"/> — user357812
– user357812, Commented Apr 8, 2011 at 15:13
@Alejandro: Sorry, I saw your comment after submitting my answer. I prefer to answer such questions -- don't have enough time to find a duplicate. And actually, redundancy is not always a bad thing. — Dimitre Novatchev
– Dimitre Novatchev, Commented Apr 9, 2011 at 4:35

oiavorskyi · Accepted Answer · 2011-04-08 14:54:07Z

2

I will take wild guess and assume you're interested in converting variable to node set in order to use it later in XPath. This could be done using extension function exsl:node-set(). The documentation have examples of usage.

Quote:

This use case shows the result of using exsl:node-set() to convert a result tree fragment to a node-set.

source

<doc>
   <one />
   <two />
   <three />
   <four />
</doc>

stylesheet

<!--  Test exslt:node-set applied to a result tree fragment  -->
<xsl:variable name="tree">
   <a>
      <b>
         <c>
            <d />
         </c>
      </b>
   </a>
</xsl:variable>
<xsl:template match="/">
   <out>
      <xsl:value-of select="count(exslt:node-set(//*))" />
   </out>
</xsl:template>

result

<out xmlns:exslt="http://exslt.org/common">5</out>

answered Apr 8, 2011 at 14:54

oiavorskyi

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1 Comment

user433023 Over a year ago

exslt is undefined even after adding the namespace.

Dimitre Novatchev · Accepted Answer · 2011-04-09 04:32:42Z

1

Use:

<xsl:variable name="SyncPath"
    select="/combinedxml/com.csc_PolicySyncRs/*[name()=$NodeName]"/>

answered Apr 9, 2011 at 4:32

Dimitre Novatchev

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Comments

Michael Kay · Accepted Answer · 2011-04-08 17:36:57Z

0

XSLT 1.0 (and indeed 2.0) has no standard facility for constructing an XPath expression as a string and then evaluating it. Many processors have an extension function to do this, variously called dyn:evaluate, saxon:evaluate, etc.

answered Apr 8, 2011 at 17:36

Michael Kay

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