Skip key index from a range of array's key in php

Question

This is only for arrays with index number. For example i have this arrays;

$array = [
  "0" => "number 1",
  "1" => "number 2",
  "2" => "number 3",
  "3" => "number 4",
  "4" => "number 5",
  "5" => "number 6",
  "6" => "number 7",
  "7" => "number 8",
  "8" => "number 9"
];

I want to skip the loop from certain range of key indexes for example, skip the foreach if the number of index is from range 0 to 5. That means we can do just like this.

foreach($array as $key => $value){
   if(array_key_exist($key, range(0,5))
      continue;
   echo $value."<br/>"
}

or we can using for... loop

for($ind = 0; $ind < count($array); $ind++){    
    if(array_key_exist($ind, range(0,5))
      continue;    
echo $arr[$ind]."<br/>" 
}

How could i skip the index without using continue or searching the array_key first ? sure the code above looks fine to me, but if i have a bunch of arrays keys and values, i think this is not a good choice.

Why not just start your for loop at 6? for($ind = 6; $ind < count($array); $ind++){ then you don't need a check in the loop at all. — Nick
– Nick, Commented May 5, 2019 at 23:40
@Nick well that's correct, but i need to do this way, rather than start the loop at 6, beacuse this is just a basic case for bigger case, so i need to know the basic how to skipped loop for certain range of index. — Gagantous
– Gagantous, Commented May 5, 2019 at 23:52
Using array_key_exists would be pretty inefficient. It would be faster to just use if ($ind >= 0 && $ind <= 5) continue;. But... without seeing the true complexity of what you are trying to do (you mention "a bunch of arrays keys and values") it's hard to offer a good solution. — Nick
– Nick, Commented May 6, 2019 at 0:01
If you want to skip arbitrary range of keys {not necessary from the beginning or end of array}, best choice would be to use print_r(array_diff_key($array, array_flip(range(3,5)))); — Agnius Vasiliauskas
– Agnius Vasiliauskas, Commented May 6, 2019 at 12:26

dWinder · Accepted Answer · 2019-05-06 04:35:29Z

2

You can use array_diff as:

$wantKeys = array_diff(array_keys($array), range(1,5));

Now all you need is loop on the $wantKeys as:

foreach($wantKeys as $k) 
    echo $array[$k]; // only wanted values

The same idea can be achieve by array_diff_keys:

$wantKeys = array_diff_key($array, array_flip(range(1,5)));

answered May 6, 2019 at 4:35

dWinder

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1 Comment

Gagantous Over a year ago

oh this is nice! but i will wait for another answer, thanks for the answer!

Gagantous · Accepted Answer · 2019-05-06 13:15:57Z

1

You can get the slice of array from 5th index to rest,

$result = array_slice($array,5,count($array)-5, true);

array_slice — Extract a slice of the array

Note:

array_slice() will reorder and reset the integer array indices by default. This behaviour can be changed by setting preserve_keys to TRUE. String keys are always preserved, regardless of this parameter.

Demo.

edited May 6, 2019 at 13:15

Gagantous

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answered May 6, 2019 at 8:51

Rahul

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6 Comments

Gagantous Over a year ago

is there a way to make the index number not re-ordered from 0 again ?

Rahul Over a year ago

Pardon mate. But I didn't understand, what you just say

Gagantous Over a year ago

sorry, i mean, your answer make the value number 6 and the rest have the index key re-ordered from the index 0. Is it possible to kept the old index key ?, so the value number 6 still have 5 for its key.

Rahul Over a year ago

Yes its possible, pass true as last parameter. Check my updated answer

Rahul Over a year ago

Your welcome mate! FYI, I updated my answer with a note of array_slice behaviour for better understanding. Thanks for the EDIT.

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