php errors in WAMP2

Question

I have a full working php script for user activation that I wrote. Fully working in a sense that it displays no errors while on my actual web hosting, although when I am working in WAMP2 I get errors such as these.

Notice: Undefined index: type in C:\wamp\www\activate.php on line 4
Notice: Undefined index: username in C:\wamp\www\activate.php on line 5
Notice: Undefined index: gender in C:\wamp\www\activate.php on line 6
Notice: Undefined index: formvalue in C:\wamp\www\activate.php on line 29

I know what the problem is, it is because the page activation.php is both for the form submission from create.php (the form on create.php has a hidden value of 1 and if it exists then the form is submitted into the mysql db) and if the form value is not present then the user is activating their account.

When the user is activating, the variables that I have defined using $_POST and the hidden form value of 1 are not defined which is causing the errors.

My question is why are these errors not displayed when my pages are loaded on my actual hosting but are present in WAMP2? And do these errors matter, is it bad practice to have undefined variables? And if so how do I overcome the problem?

Thanks and I hope I explained that all ok.

Pascal MARTIN · Accepted Answer · 2011-04-09 21:10:06Z

1

is it bad practice to have undefined variables?

Yes

how do I overcome the problem?

By not using variables that don't exist.

Or by using variables that have been initialized with a default value, if the expected value has not been provided.

For example :

if (isset($_POST['login'])) {
    $login = $_POST['login'];
} else {
    $login = '';
}

Or, using the ternary operator, to get something shorter :

$login = isset($_POST['login']) ? $_POST['login'] : '';

why are these errors not displayed when my pages are loaded on my actual hosting but are present in WAMP2?

If can be because are displayed on one server, and not on the other -- see display_errors.

Or it can be because the error_reporting level is not the same on the two servers.

Typically, your development server is configured to report notices (see E_NOTICE), and to display errors -- which makes things easier when it comes to finding the cause of some problems.

answered Apr 9, 2011 at 21:10

Pascal MARTIN

402k82 gold badges665 silver badges666 bronze badges

Sign up to request clarification or add additional context in comments.

2 Comments

Basic Over a year ago

Thanks for your great answer! I understand it alot better now. Just one more question as you seem to know your stuff, is there any difference in using a ternary operator and if, else statements except in tidyness of code? Which is considered best practice? Thanks again.

Pascal MARTIN Over a year ago

The result will be the same ; ternary operator allows one to do something like echo isset($_POST['login']) ? $_POST['login'] : '';, which is shorter than the equivalent with if/else ; it's not bad practice, as long as your code remains readable :-)

Aklopper · Accepted Answer · 2011-04-09 21:12:42Z

1

Your PHP is configured to show Notices, Warnings etc. on your WAMP2 configuration.

In the hosting environment this is disabled, and will probably only show critical errors.

You can find out more about error reporting : http://forums.devshed.com/php-development-5/changing-error-reporting-in-php-ini-549798.html

If you don't know where your php.ini file is, try to create a php file with the following code to show current configuration:

<?php
   phpinfo();
?>

answered Apr 9, 2011 at 21:12

Aklopper

564 bronze badges

Comments

Chvanikoff · Accepted Answer · 2011-04-09 21:10:01Z

0

http://php.net/manual/en/errorfunc.configuration.php - display_errors and display_startup_errors
Also what I want to say - its good practice to check if array key exists:

$login = isset($_POST['login']) ? $_POST['login'] : NULL;

answered Apr 9, 2011 at 21:10

Chvanikoff

1,3293 gold badges14 silver badges23 bronze badges

Comments

Lekensteyn · Accepted Answer · 2011-04-09 21:10:12Z

0

Your host has most likely error_reporting set to a value in which E_NOTICE's are not shown (E_ALL ^ E_NOTICE). I always check the existence of my variables, so no notices on undefined variables / indices are thrown. That aids me in debugging, in which I always enable E_NOTICE (error_reporting = E_ALL).

You may want to use the filter_* methods for getting POST or GET values because it also checks whether a submitted value is a string or not.

answered Apr 9, 2011 at 21:10

Lekensteyn

67k25 gold badges169 silver badges205 bronze badges

Collectives™ on Stack Overflow

php errors in WAMP2

4 Answers 4

2 Comments

Comments

Comments

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

4 Answers 4

2 Comments

Comments

Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Related