I want to convert json to a specific object.
String : "{\r\n \"Status\": \"PLANNED\"\r\n}"
I tried Newtonsoft Json namespace but it is returning a null value.
var Json= Newtonsoft.Json.JsonConvert.DeserializeObject<Model Class>(String )
I want the result in Json format so that I can extract the value from Json as "PLANNED" but I am getting a null.
PS :The model class contains two properties , Name (type of string), Value(type of Object)
var s = "{\r\n \"Status\": \"PLANNED\"\r\n}";
var obj = Newtonsoft.Json.JsonConvert.DeserializeObject<StatusModel>(s);
The model you have defined is incorrect. Your model should be like this:
public class StatusModel
{
public string Status { get; set; }
}
Now value will be extracted to this model and you can access the value like:
var value = obj.Status; //"PLANNED"
JSON Definition
JSON (JavaScript Object Notation) is a lightweight data-interchange format. It is easy for humans to read and write. It is easy for machines to parse and generate. It is based on a subset of the JavaScript Programming Language.
[Source] https://www.json.org/
JSON Newtonsoft
Json.NET is a popular high-performance JSON framework for .NET .
[Source] https://www.newtonsoft.com/json
Problem :
Your are trying to deserialize a json to an object and it's returning a null. In our context a Deserialization is process which transform a json to an object .
var Result= Newtonsoft.Json.JsonConvert.DeserializeObject<Model Class>(String);
The reason why you have a Null as result is beacause you are deserializing a json to Model, knowing that you Json does not correspond to the Model , this is why the Json need to correspond to the Model so that it can store the information of the Json.
Your Model :
The model may contain some property that are not in the json and vice versa
public class StatusModel
{
public string Status { get; set; }
}
Best Regards .
You can do it like this (using Newtonsoft Framework)
using System;
using Newtonsoft.Json;
{
public class JsonHandler : IJsonHandler
{
public IJsonModel ReadJson(IJsonModel model, StreamReader reader)
{
try
{
string jsonFromFile;
using (reader))
{
jsonFromFile = reader.ReadToEnd();
}
status = JsonConvert.DeserializeObject<model>(jsonFromFile);
}
catch (Exception ex)
{
Console.WriteLine(ex.ToString());
}
return status;
}
}
}
