It must be that I'm missing something big here. For some reason .charAt(i) returns undefined in this piece of code.
let images = {};
let alphabet = 'abcdefghijklmnopqrstuvwxyz';
let imageArray = ['a', 'b', 'c', 'd'];
for (let i = 0; i < imageArray.length; i++){
let letter = alphabet.charAt[i]; // returns undefined
images[letter] = imageArray[i];
}
console.log(images); // {undefined: "d"}
You need a function call of String#charAt
alphabet.charAt(i);
// ^ ^
instead of a property accessor with brackets.
let images = {};
let alphabet = 'abcdefghijklmnopqrstuvwxyz';
let imageArray = ['a', 'b', 'c', 'd'];
for (let i = 0; i < imageArray.length; i++) {
let letter = alphabet.charAt(i); // returns undefined
images[letter] = imageArray[i];
}
console.log(images); // {undefined: "d"}There's an error in your syntax! You want to call the alphabet.charAt function, of course. But you're doing charAt[i] instead of charAt(i). Square brackets are the syntax for accessing a property of an array/object by a variable (i), so you end up getting a property of the function charAt - for example charAt[0]. But that doesn't exist, so it just evaluates to undefined.
So, to fix this, just replace the square brackets (charAt[i]) with parentheses (charAt(i)). You always use parentheses to call a function, not square brackets.
You have to call the .charAt() function as a function like .charAt(i) instead of .charAt[i]
Here is it!, alphabet.charAt() is function, not array. change [] to () and it starts to work.
let images = {};
let alphabet = 'abcdefghijklmnopqrstuvwxyz';
let imageArray = ['a', 'b', 'c', 'd'];
for (let i = 0; i < imageArray.length; i++){
let letter = alphabet.charAt(i); // returns undefined
images[letter] = imageArray[i];
}
console.log(images); // {undefined: "d"}
