Python module has no attribute while the attribute exists

Question

Taking help from here, I was writing my own package. I have a folder filter which contains __init__.py (completely empty) and pca.py. pca.py has a class pca and that class has a method performPCA which takes two arguments. Then, I have this code:

from filter import pca
....
pca.performPCA(x,2)

When I run this, I'm getting an error

AttributeError: module 'filter.pca' has no attribute 'performPCA'

I know this question has an answer here, but I have everything that answer asks (the only difference is that my __init__.py is empty, which I think is totally fine). Please tell me where am I wrong. Thanks!

test.py goes as:

from filter import pca
print(pca)
import pandas as pd

x=pd.read_csv('Assignment-DS_gene_data.csv')
meta=pd.read_csv('Assignment-DS_Meta_data_sheet_.csv')
x.rename(columns={'Unnamed: 0':'col1'}, inplace=True )
del x['symbol']
del x['col1']
p=pca.pca2
#print(p)
xNew=p.performPCA(x,2)

pca.py goes as:

import pandas as pd
import matplotlib
import matplotlib.pyplot as plt
from sklearn.decomposition import PCA
from mpl_toolkits.mplot3d import Axes3D

class pca2:
    #Choose this method if only projected data is required
    def perfromPCA(self,data,nComp):
        pcaModel = PCA(n_components=nComp)
        principalComponents = pcaModel.fit_transform(data)
        colNames = []
        for i in range(1,nComp+1):
            colNames.append('PC '+str(i))
        principalDf = pd.DataFrame(data = principalComponents
             , columns = colNames)
        return principalDf

    #Choose this method if plot and projected data both are required
    #For this, nComp can either be 2 or 3
    def performPCAPlot(self,data,nComp,metaData,column):
        principalDf = performPCA(data,nComp)
        if nComp == 2:
            plt.scatter(principalDf,data=metaData['column'])
            #plt.xlabel('PC1')
            #plt.ylabel('PC2')
            plt.show()
        else:
            fig = plt.figure()
            #to do
        return principalDf

Comments are not for extended discussion; this conversation has been moved to chat. — samliew
– samliew, Commented May 29, 2019 at 11:26

MePsyDuck · Accepted Answer · 2019-05-29 11:06:35Z

0

Since you have another class inside pca.py, you should try creating an object first and then accessing it.

from filter import pca
....
p = pca()
p.performPCA(x,2)

edited May 29, 2019 at 11:06

answered May 29, 2019 at 10:31

MePsyDuck

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7 Comments

Ankit Kumar Over a year ago

I'm sorry but it isn't working. I'm getting the error 'pca' object has no attribute 'performPCA'

MePsyDuck Over a year ago

Did you try debugging? Maybe add a breakpoint and check what actually pca is and what attributes it does have?

Ankit Kumar Over a year ago

This is the p in your code: <filter.pca.pca object at 0x7f61f2899e48>

MePsyDuck Over a year ago

I meant like an actual debugging using IDE, not just print statements.

MePsyDuck Over a year ago

Try PyCharm CE. stackoverflow.com/questions/23941580/….

|

lidrariel · Accepted Answer · 2019-05-29 11:17:57Z

-1

Create an object first and then call the function on that object.

myPCA = pca()
myPCA.performPCA(x,2)

Edit

You are creating a python package by adding the _ init _.py file in the filter directory further reading subsection 6.4

You can import and use it like this (working for me with python 3.7.0)

from filter.pca import pca

myPCA = pca()
myPCA.performPCA(2,2)

or after renaming the class to pca2:

from filter.pca import pca2

myPCA = pca2()
myPCA.performPCA(2,2)

edited May 29, 2019 at 11:17

answered May 29, 2019 at 10:35

lidrariel

796 bronze badges

1 Comment

OSainz Over a year ago

The proper instantiation should be pca.pca2()

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