How to return custom response when validation has fails using laravel form requests

Question

When we use Laravel Form Requests in our controllers and the validation fails then the Form Request will redirect back with the errors variable.

How can I disable the redirection and return a custom error response when the data is invalid?

I'll use form request to GET|POST|PUT requests type.

I tried the Validator class to fix my problem but I must use Form Requests.

$validator = \Validator::make($request->all(), [
    'type' => "required|in:" . implode(',', $postTypes)
]);

if ($validator->fails()) {
    return response()->json(['errors' => $validator->errors()]);
}

laravel.com/docs/5.8/validation#customizing-the-error-messages — Gaurav Gupta
– Gaurav Gupta, Commented Jun 4, 2019 at 6:46
I need only disable redirection and return FormRequest errors — Andreas Hunter
– Andreas Hunter, Commented Jun 4, 2019 at 6:47

N'Bayramberdiyev · Accepted Answer · 2019-11-02 20:49:43Z

19

Creating custom FormRequest class is the way to go.

namespace App\Http\Requests;

use Illuminate\Contracts\Validation\Validator;
use Illuminate\Validation\ValidationException;
use Illuminate\Http\Exceptions\HttpResponseException;

class FormRequest extends \Illuminate\Foundation\Http\FormRequest
{
    protected function failedValidation(Validator $validator)
    {
        if ($this->expectsJson()) {
            $errors = (new ValidationException($validator))->errors();
            throw new HttpResponseException(
                response()->json(['data' => $errors], 422)
            );
        }

        parent::failedValidation($validator);
    }
}

Class is located in app/Http/Requests directory. Tested & works in Laravel 6.x.

answered Nov 2, 2019 at 20:49

N'Bayramberdiyev

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3 Comments

Van Tho Over a year ago

I've finally found your answer, exactly what I need.

Nebster Over a year ago

Thanks for this answer. Is there a way to do this globally for all form requests? Or in a midlleware?

N'Bayramberdiyev Over a year ago

@Nebster You can just extend this class in your other form request classes.

matiaslauriti · Accepted Answer · 2021-05-23 16:52:31Z

1

This is the same but written differently:

protected function failedValidation(Validator $validator)
{
    $errors = (new ValidationException($validator))->errors();

    throw new HttpResponseException(
        response()->json([
            'message' => "",
            'errors' => $errors
        ], JsonResponse::HTTP_UNPROCESSABLE_ENTITY)
    );
}

edited May 23, 2021 at 16:52

matiaslauriti

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answered Dec 27, 2020 at 6:28

AlmoDev

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Comments

Roman Meyer · Accepted Answer · 2019-06-04 06:48:08Z

0

Base class FormRequest has method failedValidation. Try to override it in your FormRequest descendant

use Illuminate\Contracts\Validation\Validator;

class SomeRequest extends FormRequest
{
    ...

    public function failedValidation(Validator $validator)
    {
        // do your stuff
    }
}

answered Jun 4, 2019 at 6:48

Roman Meyer

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11 Comments

Andreas Hunter Over a year ago

Error message:

Declaration of App\Http\Requests\PostCreate::failedValidation(App\Http\Requests\Validator $validator) should be compatible with Illuminate\Foundation\Http\FormRequest::failedValidation(Illuminate\Contracts\Validation\Validator $validator)

Roman Meyer Over a year ago

it seems you didn't add use of Validator

Andreas Hunter Over a year ago

I've use Validator and also tired \Validator but not work

Roman Meyer Over a year ago

you should use concrete use Illuminate\Contracts\Validation\Validator;

Andreas Hunter Over a year ago

I want validate data using Form Requests inside API routes and return errors instead of redirect. @Roman Bobrik

|

shaedrich · Accepted Answer · 2022-12-15 11:24:36Z

0

use this on function dont forget to take on top // use App\Http\Requests\SomeRequest;

$validatedData = $request->validated();
\App\Validator::create($validatedData);

create request php artisan make:request SomeRequest ex. use Illuminate\Contracts\Validation\Validator;

class SomeRequest extends FormRequest
{
   public function rules()
    {
        return [
            'health_id'      => 'required',
            'health'         => 'required',
        ];
    }
 
}

edited Dec 15, 2022 at 11:24

shaedrich

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answered Jun 4, 2019 at 8:27

iAmGroot

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Comments

marc_s · Accepted Answer · 2023-07-08 07:15:31Z

0

Add this function to your custom request:

use Illuminate\Foundation\Http\FormRequest;
use Illuminate\Contracts\Validation\Validator;
use Illuminate\Http\Exceptions\HttpResponseException;
use Illuminate\Http\JsonResponse;

protected function failedValidation(Validator $validator)
{
    throw new HttpResponseException(
        response()->json([
            'errors' => $validator->errors(),
        ], JsonResponse::HTTP_UNPROCESSABLE_ENTITY)
    );
}

edited Jul 8, 2023 at 7:15

marc_s

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answered Jul 1, 2023 at 10:05

rahali badr eddine

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