I have this folder structure:
--test
first.py
--numpad
second.py
third.py
in the first.py i have this line of code:
from numpad import second
and in the second.py file i have this:
import third
but in the test folder when i run
python first.py
i get this error message:
ModuleNotFoundError: No module named 'third'
note: i have also tried adding __init__.py to my numpad folder but it didnt work
Since the python interpreter is started within test, that's where it looks for imports. You can learn about pythons's search behavior for imports through the docs, if you're interested in the details.
To solve your problem, there are a bunch of ways to do it, the best one depending on how you plan to use your code. If you plan to write a library, it might make sense to package it, which would give you access to a global namespace that you can use.
But if you just want it to work right now, and only ever are going to run the interpreter from the same place (i.e. your test folder), defining the third file as a local one should do it:
second.py
from . import third
third.py
print('third here, not an import error')
This works for me:
~/test$ tree .
.
├── first.py
└── numpad
├── second.py
└── third.py
~/test$ python3.6 first.py
third here, not an import error
I might be wrong on this, but I'm pretty sure you'd have to set up your environment variable to look in that specific folder. Which would be way more of a hassle than just adding your homemade modules to your default modules folder.
print(sys.path)
import secondin second.py, or is that supposed to beimport third?numpadis supposed to be a python module. You can tell it that it is one by adding an empty__init__.pyfile into thenumpadfolder.__init__.pyin numpad folder but didnt work__init__.pystuff is python2. Next thing to try would be to do an explicitly local import forthird, i.e.from . import third. Since your interpreter runs at a level wherethirdis not visible, this might be necessary