How to remove multiple items from nested list in python 3, without using a list comprehension? And at times Indexerror came how to handle that?
split_list =[["a","b","c"],["SUB","d","e",],["f","Billing"]]
rem_word = ['SUB', 'Billing', 'Independent', 'DR']
for sub_list in split_list:
for sub_itm in sub_list:
if sub_itm not in rem_word:
print(sub_itm)
Output Comes like this:
a
b
c
d
e
f
Expected Output:
split_list =[["a","b","c"],["d","e",],["f"]]
You can use always use a list-comprehension. Get all the words to be removed in a separate list and try this :
>>> split_list =[["a","b","c"],["SUB","d","e",],["f","Billing"]]
>>> rem_word = ['SUB', 'Billing', 'Independent', 'DR']
>>> output = [[sub_itm for sub_itm in sub_list if sub_itm not in rem_word] for sub_list in split_list]
[['a', 'b', 'c'], ['d', 'e'], ['f']]
If you want to do it without list comprehension, you need to declare a vacant list to append each new sub-list and also a new vacant sub-list to append all new sub-items. Check this :
output2 = []
for sub_list in split_list:
new_sub_list = []
for sub_itm in sub_list:
if sub_itm not in rem_word:
new_sub_list.append(sub_itm)
output2.append(new_sub_list)
It outputs the same :
[['a', 'b', 'c'], ['d', 'e'], ['f']]
You could simply use map and filter
split_list = [["a", "b", "c"], ["SUB", "d", "e", ], ["f", "Billing"]]
remove_list = ["SUB", "Billing", "INDEPENDENT", "DR"]
split_list = list(map(lambda x: list(filter(lambda i: i not in remove_list, x)), split_list))
print(split_list)
[[x for x in z if x!='SUB'] for z in split_list]
keep in mind that it is a nested list. Treat x as the sub element and z as the element. Also keep in mind that the above code will delete all 'SUB'. just for deleting the first instance use remove.
