How to map and append values from one list to other list python 3?
in_put_1 = [["a alphanum2 c d"], ["g h"]]
in_put_2 = [["e f"], [" i j k"]]
output = ["a alphanum2 c d e f", "g h i j k"]
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is the output a flat list? the output must be sorted? by individual element?Adam.Er8– Adam.Er82019-06-13 11:53:08 +00:00Commented Jun 13, 2019 at 11:53
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Possible duplicate of Get difference between two listsAmine Messaoudi– Amine Messaoudi2019-06-13 11:54:10 +00:00Commented Jun 13, 2019 at 11:54
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@AmineMessaoudi this isn't asking for diff, it's merging themshriakhilc– shriakhilc2019-06-13 11:54:43 +00:00Commented Jun 13, 2019 at 11:54
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it should be merged and no sortingsuba– suba2019-06-13 11:56:26 +00:00Commented Jun 13, 2019 at 11:56
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why do you need array of single string? is it comma separated?Kousik– Kousik2019-06-13 11:58:13 +00:00Commented Jun 13, 2019 at 11:58
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4 Answers
You can concatenate the strings in the sublists together while iterating over the two lists together using zip, stripping the individual strings to get rid of surrounding whitespaces in the process
[f'{x[0].strip()} {y[0].strip()}' for x, y in zip(in_put_1, in_put_2)]
To do it without zip, we would need to explicitly use indexes to access elements in the list
result = []
for idx in range(len(in_put_1)):
s = f'{in_put_1[idx][0].strip()} {in_put_2[idx][0].strip()}'
result.append(s)
The output will be
['a alphanum2 c d e f', 'g h i j k']
answered Jun 13, 2019 at 11:54
Devesh Kumar Singh
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Comments
>>>map(lambda x,y: x[0]+" "+y[0],in_put_1,in_put_2)
['a alphanum2 c d e f', 'g h i j k']
1 Comment
TrebledJ
N.B. In Python 3,
map returns a generator and needs to be converted to list first before obtaining the output in the form of a list.[' '.join(element1+element2) for (element1,element2) in zip(in_put_1,in_put_2) ]
Comments
a = [["a alphanum2 c d"], ["g h"]]
b = [["e f"], [" i j k"]]
c = []
for (a1, b1) in zip(a,b):
c.append(''.join([str(a) + b for a,b in zip(a1,b1)]))
print(c)