Need to find the Css-selector path

Question

I have the path in the HTML style:

    <div class="BaseL">
        <ul class="list">
            <li draggable="true" class="listEntry" id="ItemList.item.0" widgetid="ItemL.item.0" >

The code that I have used is: driver.findbyElement(By.cssSeelector(".BaseL.list.item.0"))

Its not able to find it by id, tried webdriver.wait (didn't work). But even the cssSelector isnt working, can anyone please help me to find the cssSelector? Thanks.

You have typos in your code to select the element.

TylerH
– TylerH

2019-06-13 21:10:54 +00:00
Commented Jun 13, 2019 at 21:10 — TylerH
– TylerH, Commented Jun 13, 2019 at 21:10

IPolnik · Accepted Answer · 2021-01-27 15:52:35Z

1

If you want to find your element by Id:

driver.findbyElement(By.cssSelector(".ItemList.item.0"));

by Class:

driver.findbyElement(By.className("#listEntry"));

edited Jan 27, 2021 at 15:52

answered Jun 13, 2019 at 20:54

IPolnik

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1 Comment

Vardhman Patil Over a year ago

@IPonik please make correction in your answer. Both line showing css selector with little grammer mistake

supputuri · Accepted Answer · 2019-06-13 21:11:09Z

0

Here is the correct CSS.

You have to mask the . in the li id with \

.BaseL .list  #ItemList\.item\.0

answered Jun 13, 2019 at 21:11

supputuri

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Comments

undetected Selenium · Accepted Answer · 2019-06-13 21:26:06Z

0

You can use either of the following css-selectors:

"div.BaseL>ul.list>li.listEntry[id^='ItemList'][widgetid$='0']"

PS: As it is a draggable element you have to induce WebDriverWait

answered Jun 13, 2019 at 21:26

undetected Selenium

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