How to sort array by date but missing out the first array item

Question

I want to sort an array by date. But ignore the first item in the array. Any help would be much appreciated.

I have this currently:

articles.sort(function(a,b){
    return new Date(b.published) - new Date(a.published);
});

my array looks like this:

[
    {id: 1, published: Mar 12 2012 08:00:00 AM}, 
    {id: 2, published: Mar 9 2012 08:00:00 AM},
    {id: 3, published: Mar 15 2012 08:00:00 AM},
    {id: 4, published: Mar 22 2012 08:00:00 AM},
    {id: 5, published: Mar 8 2012 08:00:00 AM}
];

I just need to sort everything by date from id 2 - 5

What I have sorts everything.

Thanks

Your function relies on a published property that doesn't exist in the array you provided. Please update your post as necessary. — Tanner
– Tanner, Commented Jun 18, 2019 at 21:20
you want to ignore the first element in the array after sorting or before sorting — saketh
– saketh, Commented Jun 18, 2019 at 21:22

dehart · Accepted Answer · 2019-06-18 21:30:00Z

1

Use the shift() to remove the first element and unshift() to put it back at the first position:

var first = articles.shift();
articles.sort(function(a,b){
    return new Date(b.published) - new Date(a.published);
});
articles.unshift(first);

answered Jun 18, 2019 at 21:30

dehart

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Comments

abeyaz · Accepted Answer · 2019-06-18 21:25:20Z

1

Then, you can shift the first row, and readd after sorting.

var articles = [
    {id: 1, published: "2018-01-09"}, 
    {id: 2, published: "2019-01-01"},
    {id: 3, published: "2019-01-04"},
    {id: 4, published: "2019-01-03"},
    {id: 5, published: "2019-01-02"}
];
var first = articles.shift();
articles.sort((a, b) => {
    return new Date(b.published) - new Date(a.published);
});
articles.unshift(first);
console.log(articles);

answered Jun 18, 2019 at 21:25

abeyaz

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1 Comment

dehart Over a year ago

You've beat me to it. I am typing to slow =)

Akrion · Accepted Answer · 2019-06-18 21:48:59Z

1

You can simply exclude the id:1 from your Array.sort by returning 1 if the id matches 1:

let dates = [ {id: 1, published: 'Mar 12 2012 08:00:00 AM'}, {id: 2, published: 'Mar 9 2012 08:00:00 AM'}, {id: 3, published: 'Mar 15 2012 08:00:00 AM'}, {id: 4, published: 'Mar 22 2012 08:00:00 AM'}, {id: 5, published: 'Mar 8 2012 08:00:00 AM'} ];

let result = dates.sort((a,b) => 
   a.id == 1 || b.id == 1 ? 1 : new Date(a.published) - new Date(b.published))

console.log(result)

This way you would not need to concat, slice or shift anything.

answered Jun 18, 2019 at 21:48

Akrion

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Comments

Jack Bashford · Accepted Answer · 2019-06-18 21:24:10Z

0

To ignore the first item in the array, sort on the sliced array, and then merge with the first item. Also note that the timestamp needs to be a string - currently its invalid.

const articles = [{id:1,published:"Mar 12 2012 08:00:0 AM"},{id:2,published:"Mar 9 2012 08:00:0 AM"},{id:3,published:"Mar 15 2012 08:00:0 AM"},{id:4,published:"Mar 22 2012 08:00:0 AM"},{id:5,published:"Mar 8 2012 08:00:0 AM"}];
const res = [].concat(articles[0], articles.slice(1).sort(({ published: a }, { published: b }) => new Date(a) - new Date(b)));
console.log(res);

.as-console-wrapper { max-height: 100% !important; top: auto; }

answered Jun 18, 2019 at 21:24

Jack Bashford

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