I did solve the problem with this post:How to take an action when all ajax calls in each loop success? . So at the end I counted how many times I have to launch the request, than I have variable inside which decreases each time and when it hits 0 I launch the function. This way my problem is solved.
Probably this question is a duplicate of How to take an action when all ajax calls in each loop success? this since this kinda answers the question. Let me check and than I don't know, maybe I'll remove my question. I run same function with different url ajax requests with loop and I want a way to make sure I continue code only after the function returns all the data and only after continues the code. With while I can only check if function was sent one time and forwarded the result I want to make sure the function was run multiple times and I got response for each of the requests. Is this a duplicate?
If I run my function with an AJAX request I can use when to make sure the result was forwarded and only afterwards run the next code.
However if I run the function multiple times with different URLs each time then I can't make sure that all the requests are finished and I don't know how to check.
var somearray['test','car','menu'];
var array=[];
function test(thislink){
return $.ajax({
type: "GET",
url:"http://somewhere"+thislink,
success: function(response)
{
array.push(response);
}
});
}
for(i=0; i<somearray;i++){
test(somearray[i]);
}
$.when(test()).then(function( ) {
//so first request would run.
console.log(array[0]); //would return something
//while array[1] and higher may return undefined.
console.log(array[1]); // undefined. I rad that I have to use $.when.apply but I don't understand how to do that.
} );
//if i do that when will only make sure first request is success but if I try to get other url's requests probably they will be undefined.
functioninside aforloop ?!!