Error while running an array within function in python

Question

RuntimeWarning: divide by zero encountered in double_scalars While trying to insert array to an function

import numpy as np
import random

def lagrange(x, y, x_int):
    n = x.size
    y_int = 0

    for i in range(0, n):
        p = y[i]
        for j in range(0, n):
            if i != j:
               p = p * (x_int - x[j]) / (x[i] - x[j])
        y_int = y_int + p
    return [y_int]

x = []
y = []
for i in range(1000):
   x.append(random.randint(0,100))
   y.append(random.randint(0,100))

fx = 3.5
print(lagrange(np.array(x),np.array(y),fx))

i expected to have 1000 iteration of output of an output, any solution to these problems?

to handle zero division error, use np.divide(): docs.scipy.org/doc/numpy-1.14.0/reference/generated/… — Masoud
– Masoud, Commented Jul 6, 2019 at 20:48

M Somerville · Accepted Answer · 2019-07-06 20:14:09Z

2

Your error message refers to a function not mentioned in your code. But I assume the issue is because x[i] and x[j] could be the same number, and therefore you are dividing by zero on your p = p * (x_int - x[j]) / (x[i] - x[j]) line, which is not possible. You will need to add an exemption to do something different in the case x[i] equals x[j].

answered Jul 6, 2019 at 20:14

M Somerville

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hoodakaushal · Accepted Answer · 2019-07-06 20:15:18Z

2

Since you're generating your x array randomly from a range of (0,100), and the array size is 1000, it's guranteed that x[i] = x[j] for some i,j. You need to ensure elements in x are unique.

See: How do I create a list of random numbers without duplicates?

answered Jul 6, 2019 at 20:15

hoodakaushal

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Brad · Accepted Answer · 2019-07-06 20:26:03Z

0

In your nested loop could it be that you meant to do if x[i] != x[j]:

Those would be the values you wouldn't want to be the same in your division.

answered Jul 6, 2019 at 20:26

Brad

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