How to get missing value from two array in linq considering duplicates

Question

a = 3 7 4 2 8 10
b = 8 3 7 4 2 8

result should 8

How can I achieve the above result while using LINQ? If it is not possible in LINQ then an alternative solution for this

var diff = b.Except(a);

I want to get the value that is not present in a. Considering duplicates. Means once 8 is missing in a. diff should be equal to 8. @Ray — akshay_zz
– akshay_zz, Commented Jul 7, 2019 at 22:03

Or Yaacov · Accepted Answer · 2019-07-07 22:22:03Z

1

var a = new List<int>(){3 ,7 ,4 ,2 ,8 ,10};
var b =new List<int>() {8 ,3 ,7 ,4 ,2 ,8};
a.ForEach(n1=>b.Remove(n1));
b.ForEach(Console.WriteLine);     //8

edited Jul 7, 2019 at 22:22

answered Jul 7, 2019 at 21:56

Or Yaacov

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3 Comments

akshay_zz Over a year ago

the diff was blank for the above query

akshay_zz Over a year ago

so either it should return 10 or 8. Basically wants to find the missing one.

Or Yaacov Over a year ago

@akshay_zz for some reason I missed the considering duplicate part, that should do the trip, if you don't want to change the original b array, just use the CopyTo method, and generate a temp one to use.

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