Python: find the word in string

Try this :

>>> kkk="I do not like that car."
>>> a=["like","dislike","hate","cool"]
>>> print(*[x for x in a if x in kkk])
like

This list comprehension is same as the following :

for x in a:
    if x in kkk:
        print(x)

Use a for loop that iterates over the list. And change your variable names to something more meaningful.

kkk="I do not like that car."
wordlist =["like","dislike","hate","cool"]
for word in wordlist:
    if word in kkk:
         print(word)

another way of doing this is using sets:

kkk="I do not like that car."
kkk_split = kkk.split(' ')
print({'like', 'dislike', 'hate', 'cool'}.intersection(kkk_split))

any won't return the found word; the best alternative is perhaps next:

keywords = ["like", "dislike", "hate", "cool"]
sentence = "I do not like that car."

try:
    word = next(k for k in keywords if k in sentence)
    print(word)
except StopIteration:
    print('Not found')

If you don't want to handle an exception and instead get None:

word = next((k for k in keywords if k in sentence), None)

For your case, in keyword cause conflicting result. For example, the snippet below:

sentence = "I do dislike that car."
opinion = ["like","dislike","hate","cool"]
for word in opinion:
    if word in sentence:
        print(word)

prints both like and dislike. Instead, you can use regular expression zero-width word boundary \b for accurate result as:

import re

sentence = "I do dislike that car."
opinion = ["like","dislike","hate","cool"]
for word in opinion:
    if re.search(r'\b'+word+r'\b', sentence):
        print(word)

which prints dislike only.