how to create hierarchically structured folder using for each loop php?

Question

i have create hierarchically folder like folder under sub folder if exist samename folder than skip create folder and enter those directory and create nextone folder foldername taken from array

example

$folderarray = array('0'=>'8','1'=>'8','6'=>'9');

here array value 8 ,8 ,9 is folder name and i have try to create first folder name 8 than second create folder name 8 under folder 8 than create folder name 9 under folder name 8 structure like 8 under => 8 under => 9

how to do?

i have try using foreach like this but not create properly

foreach ($folderarray as $path){
   $source = "D:/xampp/htdocs/xyz/img/";
    $chkpath = $source.$path;

    if (!file_exists($chkpath)) {

        mkdir($chkpath, 0777, true);
        $source = $chkpath;


    }
    else{
        $source = $chkpath;
        continue;
    }
}

not create properly? maybe the parent folder has permission that blocks you from creating the folder? — aljx0409
– aljx0409, Commented Jul 17, 2019 at 6:32
folder created but not the proper way like folder under folder — pranay
– pranay, Commented Jul 17, 2019 at 6:35
So reading from the code, it seems like its creating folder /8 then inside folder /8, there is another folder /8 and then inside there is folder /9 right? — aljx0409
– aljx0409, Commented Jul 17, 2019 at 6:37
yes , i have create folder 8 than under create 8 than create 9 under 8 — pranay
– pranay, Commented Jul 17, 2019 at 6:40

patel jay · Accepted Answer · 2019-07-17 06:48:49Z

1

you have mistake creating path after create someone folder you have forgot / in new path

try to like this

$folderarray = array('0'=>'8','1'=>'9','6'=>'1');

$source = "D:/xampp/htdocs/xyz/img/";

foreach ($folderarray as $path){

    $chkpath = $source.$path;
    if (!file_exists($chkpath)) {
        mkdir($chkpath, 0777, true);
        $source = $chkpath.'/';


    }
    else{
        $source = $chkpath.'/';

    }


}

answered Jul 17, 2019 at 6:48

patel jay

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aljx0409 · Accepted Answer · 2019-07-17 06:47:44Z

0

You might want to do:

$source = "D:/xampp/htdocs/xyz/img";
foreach ($folderarray as $path){
    $chkpath = $source . "/" . $path;

    if (!file_exists($chkpath)) {
        mkdir($chkpath, 0777, true);
        $source = $chkpath;
    } else {
        $source = $chkpath;
        continue;
    }
}

answered Jul 17, 2019 at 6:47

aljx0409

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