How to sort an array of arrays based on the 2nd value of children arrays [duplicate]

Question

Perhaps we have an array of arrays such as this:

["a", "11.36"]
["b", "12.13"]
["c", "11.00"]

Is there a simple function to be able to sort them based on the 2nd index?

I know how to solve it... I just wanted an absurdly easy question that people can reference because it took me too long to research. — Nicholas Hazel
– Nicholas Hazel, Commented Jul 17, 2019 at 8:11
Fair enough. I just wanted to post something I struggled to find with some verbiage I wasn't using. I'll delete it in the morning if necessary. — Nicholas Hazel
– Nicholas Hazel, Commented Jul 17, 2019 at 8:27

jank · Accepted Answer · 2019-07-17 08:14:11Z

0

const a = [
  ["a", "11.36"],
  ["b", "12.13"],
  ["c", "11.00"]
];

a.sort(([,a], [,b]) => a - b)
console.log(a)

answered Jul 17, 2019 at 8:14

jank

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Comments

mitesh7172 · Accepted Answer · 2019-07-17 08:15:39Z

0

You can try this:

let arr = [["a", "11.36"], ["b", "12.13"], ["c", "11.00"]]
arr = arr.sort(function(a,b) {
    return a[1] - b[1];
});
    
console.log(arr)

answered Jul 17, 2019 at 8:15

mitesh7172

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