I need to pass arguments from outer function to inner function

Question

I need to use variable arguments to inner function.

I have this function that I cannot change:

function SUM() { 
  var res = 0;
  for (var i = 0; i < arguments.length; i++) {
    res += (arguments[i]==null?0:arguments[i]);
  }
  return mSum(res);
}

Well because this function sometimes returns extra decimal values, I want to wrap it into a function like

function MySUM( return parseFloat(SUM().toFixed(10))    );

the problem is that SUM function cannot read "arguments" of outer function that calls it, and I don't know how to pass this arguments from mySUM to inner SUM function. What I expect is some like this

function MySUM( return parseFloat(SUM(arguments).toFixed(10))    );

but it doesn't work.

So you're adding a wrapper to another wrapper? Can you change mSum()? You shouldn't need to check for null since js will treat it like 0 in this case. res += arguments[i]; should give you the same result for res. — Daniel Gale
– Daniel Gale, Commented Jul 18, 2019 at 15:25

Mureinik · Accepted Answer · 2019-07-18 15:25:46Z

1

You can spread the arguments using the ... operator, send them to the SUM function:

function MySUM() {
    return parseFloat(SUM(...arguments).toFixed(10));
    // Here --------------^
}

answered Jul 18, 2019 at 15:25

Mureinik

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Devashish · Accepted Answer · 2019-07-18 15:23:12Z

1

You can do it like this:

function MySUM(arguments) {
    return parseFloat(SUM(arguments).toFixed(10))
}

answered Jul 18, 2019 at 15:23

Devashish

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