How to configure in Rollup that will generate only single output file from multiple input files?

Question

When configuring Rollupjs to generate a library, if the input is an array which consists of multiple javascript files. How can we do to these inputs will be generated in just a single output js file?

export const lgService = {
  input: [
    './src/app/services/livegiver/lgservices.js', 
    './src/app/services/readable-stream.js'
  ],
  output: {
    file: outputPath + 'LiveGiver/index.js',
    format: 'es'
  }
}

Expected:

  Input: [a.js, b.js]
  Output: dist/index.js

Actual:

  Input: [a.js, b.js]
  Output: dist/a.js; dist/b.js

Rich Harris · Accepted Answer · 2019-07-23 10:58:30Z

4

You can't — multiple inputs implies multiple outputs. To do what you're describing, you'll need to have a single entry module that looks something like this:

import './app/services/livegiver/lgservices.js';
import './app/services/readable-stream.js';

If you need to generate that module dynamically you could use something like rollup-plugin-virtual.

answered Jul 23, 2019 at 10:58

Rich Harris

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Naresh Manthena · Accepted Answer · 2021-10-19 06:33:00Z

3

You can import all your js files into index.js. and export from index.js like the below

export { default as YourComponent} from "component path";

then in your rollup.config.js file.

export const lgService = {
  input: './src/app/index.js',
  output: {
    file: outputPath + '/index.js',
  }
}

this is tested in rollup v2.57.0

answered Oct 19, 2021 at 6:33

Naresh Manthena

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