I'd love to have a function return a number of results function of the parameters I give it.
I've already tried googling etc but didn't have any luck
For example:
def function(x, i_add = False):
if i_add == True:
y = x+1
return x, (Y)?
Given the example the results I'd like to have are:
function(3) -> 3
function(3, True) -> 3, 4
function(3, False) -> 3
I'm on python 2.7
With simple condition on return statement:
def function(x, i_add = False):
return (x, x+1) if i_add else x
You can return as many you need, If you return multiple values it will be tuple and if you return one value it will be just value
def function(x, i_add = False):
if i_add == True:
return x,x+1
else:
return x
re=function(10,True) # or a,b=function(10,True)
print(type(re)) #tuple (10,11)
r=function(10,False)
print(type(r)) # int 10
You can do this using a Tuple:
def function(x,i_add = False):
if i_add:
y = x+1
return x, y;
else:
return x
var1, var2 = function(3, True)
print(var1)
print(var2)
you can find more on geeksforgeeks: https://www.geeksforgeeks.org/g-fact-41-multiple-return-values-in-python/
A DRY (Don’t repeat yourself) version using tuple concatenation
def function(x, i_add=False):
return (x,) + ((x+1,) if i_add else ())
Useful, if you have many default return arguments (e.g. u,v,w,x,y,[z]).
It always returns a tuple.
