i have two arrays like these
var arr1 = ["han", "Ji", "Kidda", "Ho", "Tusi"]
var arr2 = ["hello", "Ji"]
i want to create a new dictionary that have first element of first array and first element of second array and so on. when the third element of first array comes it should again get the first element of second array.
for example:-
dict = ["han" : "hello", "Ji" : "Ji", "Kidda" : hello, "Ho" : "Ji", "Tusi" : "hello"]
If the second array has 2 items you can do
var dict = [String: String]()
for (index, item) in arr1.enumerated() {
dict[item] = arr2[index % 2]
}
I believe this is what you're looking for (using arr1 as the keys and arr2 as the values repeating them as necessary):
var arr1 = ["han", "Ji", "Kidda", "Ho", "Tusi"]
var arr2 = ["hello", "Ji"]
let dict = Dictionary(uniqueKeysWithValues: zip(arr1, arr1.indices.map { arr2[$0 % arr2.count] }))
print(dict)
["Kidda": "hello", "Ji": "Ji", "han": "hello", "Ho": "Ji", "Tusi": "hello"]
Note:
Dictionaries have no specified ordering. Only the key/value pairings matter. This matches the example in your question.
Explanation:
zip is used to create a sequence of (key, value) tuples from two sequences that will become the key/value pairs for the new Dictionary. The keys come from arr1. map is used to generate the sequence of values from arr2 repeating them as many times as necessary to match the count of arr1. This sequence of (key, value) tuples is passed to Dictionary(uniqueKeysWithValues:) to turn that sequence into the desired Dictionary.
try:
var dict = ["arr1" : "hello", "arr2" : "Ji"]
then for third you can append by
dict[3] = ["arr3" : String(arr3.first())]
Try this:
var arr1 = ["han", "Ji", "Kidda", "Ho", "Tusi"]
var arr2 = ["hello", "Ji"]
var dict : [String : String] = [:]
var arr2Index = 0
for index in 0..<arr1.count {
let arr1Value = arr1[index]
if arr2Index == arr2.count {
arr2Index = 0
}
let arr2Value = arr2[arr2Index]
dict[arr1Value] = arr2Value
arr2Index += 1
}
Here's a fun way:
let arr1 = ["han", "Ji", "Kidda", "Ho", "Tusi"]
let arr2 = ["hello", "Ji"]
let arr3 = Array(repeating: arr2, count: arr1.count).joined()
let d = zip(arr1,arr3).reduce(into: [String:String]()) { $0[$1.0] = $1.1 }
