Generating random numbers unique from another variable

Question

I've generated an array of three random numbers unique from each other (no duplicates). Now I also want to make sure that all three of the random numbers are also unique from the variable "answer".

var answer = 4;

//Generating the three random numbers
var arr = [];

while (arr.length < 3) {
    var random_number = Math.floor(Math.random() * 9) + 1;
    if (arr.indexOf(random_number) == -1) { 
        arr.push( random_number );
    }
}

I cant seem to make it so that each of the three numbers is not equal to the variable 'answer'

Some programming advice: use if(arr.includes(random_number)) { instead of using indexOf() and comparing it to -1. And use let instead of var. — MultiplyByZer0
– MultiplyByZer0, Commented Aug 3, 2019 at 3:15

Jack Bashford · Accepted Answer · 2019-08-03 03:13:27Z

1

Just add another condition to your if statement:

if (arr.indexOf(random_number) == -1 && random_number != answer) {
  arr.push(random_number);
}

answered Aug 3, 2019 at 3:13

Jack Bashford

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1 Comment

Noah Over a year ago

Thanks, don't know why I didn't try that. I did try "||" though lol

Prabhat Kumar · Accepted Answer · 2019-08-03 03:19:14Z

0

add && condition also

var answer = 4;

//Generating the three random numbers
var arr = [];

while (arr.length < 3) {
    var random_number = Math.floor(Math.random() * 9) + 1;
    if (arr.indexOf(random_number) == -1 && random_number != answer) { 
        arr.push( random_number );
    }
}

answered Aug 3, 2019 at 3:19

Prabhat Kumar

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